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will also try to answer this :D

|dw:1439963429493:dw|

maybe laterrr. I'm finishing my other problems :D

|dw:1439963731904:dw|

Tag me if you get stuck anywhere c:

will do sir. Thank you!

Okay I'll start answering now!

t at 1 s
Y = 0.451 m ?

t at .250
Vf = 5m/s - (9.8)(.250)
Vf = 2.55
t at 1
Vf = -4.8 m/s

am I doing it right looool

b.) is quite confusing hmmm doI have to use 2 equations???

Exact position at 0.25 seconds will be 40+0.94 m from ground.

hmmm okay. Wait I'll try to use your concept

where did you t = 0.5??

so you mean to say 40=(-5)(t)+1/2(9.8)(t)^2 ???

I got 3.4125 s

Total time will be \(\approx 3.38~s\)