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- anonymous

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- chestercat

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- anonymous

@triciaal can you help me. You and I are the only ones online I think lol.

- anonymous

the inverse of multiplication is division and for addition is subtraction

- anonymous

okay

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## More answers

- anonymous

so, the inverse of 1/4x=4x

- anonymous

example the inverse of 6x= 1/6x

- anonymous

please answer this for me . what is the inverse of 100x?

- anonymous

so then it has to be f^-1(x) = 4x - 3

- anonymous

x/100 ?

- anonymous

nooo. the anser is 1/100x

- anonymous

another question. what is the inverse of 20x?

- anonymous

1/20x I'm confused. I hate this

- anonymous

thats is right

- anonymous

okay

- anonymous

what is the inverse of 15?

- anonymous

-15?

- anonymous

just from what you've told me I actually think it's f^-1(x) = 4x - 3 and not the first answer I had. My packet isn't doing a very good job of explaining this.

- anonymous

very correct

- anonymous

I guess I thought that the x should be in the parenthesis with the 3 but now I know that was super wrong. So thank you :)

- anonymous

Also I need to find better explanations of this, my packet does a sucky job.

- anonymous

ok

- anonymous

thanks again tho

- anonymous

Here are simple steps for inverse:
Replace f(x) with y
Switch x's and y's, so put x where y is and x where y is.
Solve for y
Replace y with f^-1(x)

- anonymous

@iambatman thank you :)

- anonymous

Yw :)

- anonymous

are you here?

- amilapsn

yeah

- anonymous

okay

- amilapsn

So the original expression will be: \(y=\frac{1}{4}x+3\) ok?

- anonymous

right

- amilapsn

Can you guess what switching \(x\) and \(y \) means?

- anonymous

okay so switching them I thought meant doing
1/4x= y+3

- anonymous

that's where I wasn't sure what I was doing.

- amilapsn

No that guess was wrong.. ;)

- amilapsn

Switching means simply interchanging...
For example:
Before switching: \(\color{blue}y=2\color{red}{x}+1\)
After switching: \(\color{red}{x}=2\color{blue}y+1\)
ok?

- anonymous

yeah okay so the 1/4 would just stay where it was initially.

- amilapsn

exactly!
So now what the answer would be?

- anonymous

it would be f^-1(x)= 4x-3?

- amilapsn

no... Not quite.
after switching what would you get?

- anonymous

okay so the problem would look like
x=1/4y+3 the inverse of addition is subtraction (like said above)

- anonymous

f^-1(x) = 4(x-3)

- anonymous

iambatman said to solve for y how would I do that?

- amilapsn

that's right!

- anonymous

so the first answer I had was right the entire time?

- anonymous

@GIL.ojei did we do it wrong the first time around? Would you say that it's right this time?

- amilapsn

yep.. BTW solving for y means expressing y in terms of x.
that means you've got \(x=\frac{1}{4}y+3\) after switching..
After solving for \(y \) means just getting \(y=4(x-3)\)

- amilapsn

ok?@GIL.ojei

- anonymous

@lily1021 IS Y=4X-12 OR 4(X-3) IN YOUR OPTION?

- anonymous

yep those were both in my options which why I was torn between them. I didn't know what made them different.

- anonymous

oh wait I missed the 12 in your post. No y=4x-12 is not in my options but 4(x-3) is

- anonymous

OK . GO WITH THAT .

- anonymous

okay thank you. and big thanks to @amilapsn for coming back and helping me through this. It means so much to me you have no idea lol :)

- amilapsn

YX @lily1021 lol :D

- anonymous

I have another similar one I have to solve but I think it would kinda be the same. Can I post so you can check? I'll do it in a new post so I can medal you.

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