anonymous
  • anonymous
.
Mathematics
jamiebookeater
  • jamiebookeater
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misty1212
  • misty1212
you do not need to graph this to do it
misty1212
  • misty1212
put in the number for x, see if you get the y
anonymous
  • anonymous
Oh really okay

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misty1212
  • misty1212
you are right however
misty1212
  • misty1212
it is \[f(x)=\sqrt{x+6}+2\]right?
anonymous
  • anonymous
yeah
misty1212
  • misty1212
so \[f(-2)=\sqrt{-2+6}+2=\sqrt{4}+2=2+2=4\]
misty1212
  • misty1212
i.e if \(x=-2\) then \(y=4\) so \((-2,4)\) is on the graph
anonymous
  • anonymous
oh I was right then? I was dying trying to graph this because it wasn't really exact but (-2, 4) was the closest.
anonymous
  • anonymous
I like your way better.
misty1212
  • misty1212
how did you graph it?q
anonymous
  • anonymous
It's on paper so I can only describe it but it was exactly on the -4 just a little under.
anonymous
  • anonymous
Your way gives me the exact thing though so that's nice.

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