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anonymous

  • one year ago

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  1. misty1212
    • one year ago
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    you do not need to graph this to do it

  2. misty1212
    • one year ago
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    put in the number for x, see if you get the y

  3. anonymous
    • one year ago
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    Oh really okay

  4. misty1212
    • one year ago
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    you are right however

  5. misty1212
    • one year ago
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    it is \[f(x)=\sqrt{x+6}+2\]right?

  6. anonymous
    • one year ago
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    yeah

  7. misty1212
    • one year ago
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    so \[f(-2)=\sqrt{-2+6}+2=\sqrt{4}+2=2+2=4\]

  8. misty1212
    • one year ago
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    i.e if \(x=-2\) then \(y=4\) so \((-2,4)\) is on the graph

  9. anonymous
    • one year ago
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    oh I was right then? I was dying trying to graph this because it wasn't really exact but (-2, 4) was the closest.

  10. anonymous
    • one year ago
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    I like your way better.

  11. misty1212
    • one year ago
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    how did you graph it?q

  12. anonymous
    • one year ago
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    It's on paper so I can only describe it but it was exactly on the -4 just a little under.

  13. anonymous
    • one year ago
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    Your way gives me the exact thing though so that's nice.

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spraguer (Moderator)
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is replying to Can someone tell me what button the professor is hitting...

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