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anonymous

  • one year ago

What is the equation of a line that passes through points (0, 4) and (-4, -8)? y = 2x + 4 y = 2x - 4 y = 3x + 4 y = 3x - 4

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  1. Nnesha
    • one year ago
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    first find the slope \[\huge\rm m=\frac{ y_2-y_1 }{ x_2-x_1}\] substitute x's and y's by their value

  2. Nnesha
    • one year ago
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    \[\large\rm (x_1 ,y_1)(x_2,y_2)=(0,4)(-4,-8)\] x's and y's

  3. anonymous
    • one year ago
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    y=2x-4

  4. Nnesha
    • one year ago
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    how did you get that ?

  5. anonymous
    • one year ago
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    idk how to do it

  6. Nnesha
    • one year ago
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    |dw:1439993754267:dw| now substitute x's and y's by their values remember first number in order represent x-coordinate so find sole fist \[\huge\rm m=\frac{ y_2-y_1 }{ x_2-x_1}\] substitute x's and y's by their value

  7. Nnesha
    • one year ago
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    slope intercept form is \[\huge\rm y=\color{reD}{m}x+b\] where m is slope and b is y-intercept first we have to find m value

  8. anonymous
    • one year ago
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    y=4x-4 like that

  9. anonymous
    • one year ago
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    +

  10. Nnesha
    • one year ago
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    |dw:1439994011436:dw| here now replace x's and y's by their valeus

  11. Nnesha
    • one year ago
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    |dw:1439994152620:dw| that's how you have to substitute variables by their numbers

  12. anonymous
    • one year ago
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    y|dw:1439994209239:dw|

  13. Nnesha
    • one year ago
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    |dw:1439994289089:dw| y_2 means 2nd y

  14. Nnesha
    • one year ago
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    now solve that fraction

  15. anonymous
    • one year ago
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    |dw:1439994310600:dw|

  16. Nnesha
    • one year ago
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    \[\huge\rm \frac{ -8-4 }{ -4-0 } = ???\]

  17. anonymous
    • one year ago
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    |dw:1439994506801:dw|

  18. Nnesha
    • one year ago
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    -8-4 = ???

  19. anonymous
    • one year ago
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    |dw:1439994601702:dw|

  20. anonymous
    • one year ago
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    |dw:1439994643265:dw|

  21. Nnesha
    • one year ago
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    no it's not equal to -4 pay attention!!

  22. anonymous
    • one year ago
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    ok

  23. Nnesha
    • one year ago
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    so -8-4 = ?? remember you should add them

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