1. Find the distance between the points (2, -3) and (5, -4).

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1. Find the distance between the points (2, -3) and (5, -4).

Mathematics
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okay so
distance formula \[\huge\rm d=\sqrt{(x_2 -x_1)^2+(y_2-y_1)^2}\] plugin x's y's values :)

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okay.
x's and y's \[\rm (x_1,y_1)(x_2 ,y_2)\]
\[d=\sqrt{?}(5-2)^2+(-4--3)\]
idk how to do that thing where it puts it in there lol
it's okay i know what you mean and yes that' right
no how to solve it
first solve the parentheses (5-2) and (-4-(-3)) and then take square
d= square root of 9+-7
-4-(-3) = ??
-7^2
lol hang on that would be
49
so d= the square root of 58
which is 7.6
right?
no no no -4-(-3) first distribute -3 by negative sign and then combine them
uhhhhhh whhaa
|dw:1439994778548:dw| ther is invisible one so multiply negative one times -3 and then add -4 there is negative sign you can't remove the parentheses ntill u multiply it with negative on
one *
what the heck. never heard of that
so -12^2
you never heard that you should multiply negative one by -3
what negative one times -3 = ?
heck to the no
3
calm down.....
okay so |dw:1439994946005:dw|
-12
ha sorry
why did you multiply -4 by 3 ? subtract it's -4+3
-1
yep right so \[\huge\rm \sqrt{(3)^2+(-1)^2}\]
screw this. i got like 20 more of em to do. whates one thing you dont understand. i got a 90 in the class anyways
I've been trying to figure these out for like 2 years and I still have no clue.
3^2 is same as 3 times 3 and 1^2 is same as 1 times 1
take square of 3 and 1and then add them together that's it
so 10
then whatever the square root of 10 is
yes right!
yea.

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