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anonymous
 one year ago
c
anonymous
 one year ago
c

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sorry, r = 2cos(phi) is an equation in spherical coordinates where phi is the polar angle, 0 <phi <pi

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it is an equation of a sphere in spherical coordinates, need it in rectangular coordinates

phi
 one year ago
Best ResponseYou've already chosen the best response.1usually people use rho rather than "r" (and use r for cylindrical coords)

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.8\(\rho = 2\cos\phi \implies \rho^2=2\rho\cos\phi = 2z\) Next replace \(\rho^2\) by \(x^2+y^2+z^2\) and you're done!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0My apologies, I am still learning the coordinate systems and standard notation. phi is the polar angle in spherical coordinates which is between zero and pi

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.8dw:1439995254724:dw

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.8Notice that in below triangle, we have \(z = \rho\cos\phi\) dw:1439995296915:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ganeshie8 thank you for your help. I see now that I can complete the square on z^2  2z to get a nice cartesian equation

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.8\(\rho = 2\cos\phi \implies \rho^2=2\rho\cos\phi = 2z\) replacing \(\rho^2\) by \(x^2+y^2+z^2\) gives \[x^2+y^2+z^2=2z\] that is the cartesian form...

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.8and yeah you may complete the square for \(z^22z\) to get a nicer one :)
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