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anything to the zero is just equal to one \[\large\rm x^0 = 1~~~~(Nnesha)^0 =1~~~~~ (anything)^0=0\]
and then apply this exponent rule \[\huge\rm (x^m)^n = x^{m \times n}\] multiply exponents

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\(\color{blue}{\text{Originally Posted by}}\) @Nnesha anything to the zero is just equal to one \[\large\rm x^0 = 1~~~~(Nnesha)^0 =1~~~~~ (anything)^0=0\] \(\color{blue}{\text{End of Quote}}\) correction: \[\rm (anything)^0=1\]
so thats 0
how ?
dont you sub
5^0 = ??
1
and (5^3)^2 = ?
but how is that the answer id we only have 0 and 5s
15,625
no don't use the calculator >.>
how i dont know how to do it with out it
use this exponent rule \[\huge\rm (x^m)^n = x^{m \times n}\] multiply outside exponent with the inside exponent of 5
how? tbh im slow i never seen this
just m and n are exponents here is an example \[\huge\rm (2^2)^3 = 2^{2 \times 3}\]
ok tbh how to put that in a calulator.
life is easy without calculator !!
pretty sure you know how to multiply numbers
not big numbers
\(\color{blue}{\text{Originally Posted by}}\) @Nnesha just m and n are exponents here is an example \[\huge\rm (2^\color{Red}{2})^\color{Red}{3} = 2^{\color{Red}{2 \times 3}}\] \(\color{blue}{\text{End of Quote}}\) here i'm just multiplying exponents
that's not a big calculator is giving you horrible answer
2x3=6
im useing sicentic caulator
right \[\huge\rm (5^3)^2= 5^{??}\]
you don't even need one.
yea
2
how did you get that ?
just multiply the exponents!!!
.-. i did
what r the exponents ??
3x2
yep right \[5^{3 \times 2}= 5^{???}\]
._______. its 6
yes right so answer is ?
yea
okay then good to go!

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