PLZ HELP Equation A: y = x + 1 Equation B: y = 4x + 5 Which of the following steps can be used to find the solution to the set of equations? x + 1 = 4x + 5 x = 4x + 5 x + 1 = 4x x + 5 = 4x + 1

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PLZ HELP Equation A: y = x + 1 Equation B: y = 4x + 5 Which of the following steps can be used to find the solution to the set of equations? x + 1 = 4x + 5 x = 4x + 5 x + 1 = 4x x + 5 = 4x + 1

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Any thoughts?
not really I'm so confused

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Other answers:

Ok, they are using the method of substitution.
ok
That is where you solve for a variable and plug it into that variable in the other equation.
Both of these equations are already solved for y.
So, we can take what y= in one equation, and plug it in for y in the other equation.
|dw:1440003635482:dw|
i thought y = 4x
I'm not sure what you mean.
in equation b
or is that just the slope formula
Equation b is close to the slope formula, y=mx+b, but it has an x instead of y.
ok
But have you followed what I have said so far?
yes
So, if you plug in x+1 for y in the second equation, what do you get?
y=4x+6?
Hm, no, if we are subbing x+1 in for y, then we don't have y anymore.|dw:1440004062537:dw|
oh
:-) Does that make sense?
yep
Cool, so what is the answer?
a
Yep!
can u do another plz?
;)
Sure
Equation C: y = 6x + 9 Equation D: y = 6x + 2 Which of the following options is true about the solution to the given set of equations? One solution No solution Two solutions Infinite solutions
Ok, well, let's see what happens if we do the same thing as the last problem.
What do you get when you sub 6x+9 for y in the second equation?
6x+9=6x+2?
Sweet! Can you simplify that?
combine like terms?
Yep
12x+9=+2??
No, to move one 6x to the other side, we need to subtract it
|dw:1440004496684:dw|
ohhhh i get it
so theres only one solution?
Sweet! So, any thoughts of what that tells us?
Hm, no. When the two equations simplify to a false statement (9 does not equal 2),
That means no solution
ohh
We can graph them to show that too.
They have the same slope, but different y intercepts
So they are parallel lines, and will never cross.
The solution is the point where the two lines cross.
one more??
Sure :-)
y = 3x + 4 2x + 3y = 10 Which of the following steps could be used to solve by substitution? 3x + 4 = 2x + 3y 2x + 3(3x + 4) = 10 2(3x + 4) + 3y = 10 3(y = 3x + 4)
Ok, any thoughts?
no
The first equation is solved for y.
So, we take what y is in terms of x, and plug it into the other equation.
Can you try to do that?
im lost, ugh and my online teacher keeps reminding me about time crunch lol
|dw:1440004939079:dw| Aw, that's frustrating!
i see
It is like the other ones, just the second equation isn't solved for y.
ho do i slove
how
We aren't supposed to solve, just substitute.
ok
|dw:1440005055460:dw|
See how I subbed the 3x+4 in for y in the second equation?
yes
That is all we have to do :-)
Which answer does that look like?
b
Right
one more, last one i promise lol
Haha, ok
d + e = 15 −d + e = −5 Label the ordered pair as (d, e). (0, 0) (10, −5) (5, 10) (10, 5)
Ok, this one we actually do have to solve. Any thoughts on how to start?
not really
Well, what happens when we add the two equations together?
we sub?
We could, but we would have to solve for one of the variables first.
ok
I would suggest to use elimination on this one. It is the easier method. :-)
ok
|dw:1440005374033:dw| What happens when we add the two equations together?
im not sure
Just take a guess
elimintion
Ok, but what equation are we left with?
i honestly don't know
|dw:1440005536799:dw| See how I added the equations together?
yes
Can you combine like terms?
ill be back in one min, my teacher is calling me
Ok
I'm back @JoannaBlackwelder
Ok, can you combine like terms?
that one is kinda hard
It is a little different. d-d is what?
d
No, it is like 2-2.
0
Right. :-)
And e+e is what?
e
No, we add the coefficients, and when there is no coefficient written it is understood to be 1. So this is 1e+1e
2
Close, 2e
oh i see
:-) And what is 15-5?
10
|dw:1440006758146:dw| Great!
See how I simplified that?
yep
Sweet, so we need to finish getting e by itself.
It is currently multiplied by 2
So, we need to divide the left side by 2 to leave just e (or 1e)
|dw:1440006877761:dw|
Good effort! But we need to divide by 2 to get e by itself, not 10
ok
|dw:1440006917075:dw|
ok
so whats my second point
Well, now that we know that e is 5, which answers do we have to choose from?
c,d
?
Are you sure that both c and d have e being 5?
c?
No, c, has e as 10.
d
Yep, that is the only answer that has e as 5. We would normally also have to find d, but they gave us a shortcut. :-)
thank u
You're welcome

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