anonymous
  • anonymous
how does csc(-120) equal to -csc(120)?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Nnesha
  • Nnesha
sin and tan are odd cos = even \[\large\rm sin(-\theta)= -\sin \theta\]\[\large\rm cos(-\theta)= \cos \theta\]\[\large\rm Tan(-\theta)= - Tan \theta\]
anonymous
  • anonymous
I still don't understand
Nnesha
  • Nnesha
what is reciprocal of sin ,cos and tan ???

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
Honestly I have no idea. I am the worst with trigonometry. I don't understand it whatsoever
Nnesha
  • Nnesha
then u need to start it over \[\large\rm sin =\frac{ 1 }{ \csc }~~\cos=\frac{ 1 }{ \sec }~~~\tan=\frac{ 1 }{ \cot }=(\frac{ \sin }{ \cos })\] reciprocal of sin is 1/csc reciprocal of cos is 1/sec reciprocal of tan is 1/cost or you can say sin /cos csc=1/sin sec=1/cos cot=1/tan csc , sec and cot are reciprocal of sin , cos and tan
Nnesha
  • Nnesha
if sin =a/b then csc = b/a
Nnesha
  • Nnesha
so if sin is odd function then csc is odd or even ?
anonymous
  • anonymous
odd
Nnesha
  • Nnesha
yes right that's how \[\huge\rm csc(-120)= - \csc(120)\]
dumbcow
  • dumbcow
another way of looking at it is using the unit circle and fact that neg angle goes clock-wise |dw:1440006652430:dw|
anonymous
  • anonymous
but I'm just not understanding how the negative comes out
dumbcow
  • dumbcow
sin refers to "y-value" , on the circle sin(-120) is the neg y-value of sin(120)
dumbcow
  • dumbcow
|dw:1440007033356:dw|
anonymous
  • anonymous
oooooh okay, i get it more now lol. thank you!
anonymous
  • anonymous
is this also true for cosine ?
Nnesha
  • Nnesha
cos = odd
Nnesha
  • Nnesha
\[\large\rm cos (-45)= \cos(45)\] |dw:1440007938868:dw| x-coordinate represents cos function
anonymous
  • anonymous
wouldn't the cosine be negative too since it's in the 3rd quadrant ?
Nnesha
  • Nnesha
yeah i was just thinking about this .. cos is also negative in 2nd quadrant
Nnesha
  • Nnesha
for odd and oven just remember sin(-x)= -sin(x) cos(-x)=cos(x) tan(-x)= -tan(x)
Nnesha
  • Nnesha
@dumbcow
anonymous
  • anonymous
so it's not true for cos of theta ?
Nnesha
  • Nnesha
yes right cos (-120) = cos(120)
Nnesha
  • Nnesha
cos is even
anonymous
  • anonymous
how do I prove that ?
anonymous
  • anonymous
my question says to pick a value of theta and to test the theory
Nnesha
  • Nnesha
i guess because cos is negative in 2nd quadrant and in 3rd quadrant so negative times negative = positive even
Nnesha
  • Nnesha
:P i just know the basic stuff don't know how to explain better than that sorry
anonymous
  • anonymous
thank you

Looking for something else?

Not the answer you are looking for? Search for more explanations.