At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
I need help with 2 and 3 2.The inequalities: Show the work for finding the inequality that defines each segment. 3.A point: Choose a point within the boundaries of the shape, and show algebraically that the point satisfies all of the inequalities
Idk for sure
@mathstudent55 @welshfella can you help me?
this sucks xD none can help me
ok @Keigh2015 can you help at all?
Sorry man I can't help
First find the equations for each of the lines
eg The line joining (4,8) and (9,13) is y = x + 4
how did you get that?
and area under that is y > x + 4
y > x + 4 is 4,8 to 9,3?
first find the slope y2 - y1 ------ = (13 - 8) / (9-4) = 1 x2 - x1 Then plug this and one of the points into the general equation y - y1 = m(x - x1) y - 13 = 1(x - 9) which simplifies to y = x + 4
now you need to do that for the other 3 lines
no (4,8) to (9,13)
So if (4,8) to (9,13) is y = x + 4
Then y2 - y1 ------ = (4 - 8) / (9 - 3) = ? x2 - x1
How would I solve that @welshfella
4-9 and -8+3
ok 4-9 is 5 and -8+3 is -5
no 9-4 and -3+ 8 I believe I mixed them up
thats 5 and 5
I swear I'm wrong just ask welsh..xD
no this line has negative slope and is at right angles to the one joining (4,8) and (9,13) so its slope is -1 y-y1 = m(x - x1) y - 8 = -1(x - 4) y = -x + 4 + 8 y = -x + 12
wow i cant believe it im so lost rn
is that for 9,3 or 9,13?
that is the equation for the line joining (4,8) and )9,3)
there are the slopes of the four lines
wow I just got ignored..:O..well then..bye
so for 9,13 to 14,8 is the same then?
sorry - i'm ok in English - not brilliant
so from 9,13 to 14,8 it would be y = -x + ?
yes but you'll need to plug in one of the points - use (9,13)
ok so it would look like
y - y1 = -1(x - x1) y1 = 13 x1 = 9
you have to always that general form y-y1 = m(x - x1)
ok so then it would look like this? y = -x + 9
y - 13 = -1(x - 9) now isolate y and simplify the RHS
y - 13 = -x + 9 now add 13 to both sides
13 and 13 so that would be y= - x + 22?
ok so that would be 9,13 to 14,8
we've just done that one
lets see what we've got so far y = x+ 4 y = -x _ 12 y = -x + 22 oh we haven't done (9,30 to (14,8)
I dont know how to start it
I 'll have to look the stuff over again I'm not sure if i'm right. Give me a minute
yea the 3 we've done are ok thats y = -x + 12 though for the line from (9,3) to (14,8) slope = 1 take the point (9 ,3) y - 3 = x - 9 y = x - 6
so theres the equation for 4 lines y = x+ 4 y = -x + 12 y = x - 6 y = -x + 22
thanks so much
yw so the inequalities are y <= x + 4 y >= -x + 12 y >= x - 6 y <= -x + 22 that defines the shaded diamond
ok thanks so much