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anonymous

  • one year ago

Solve x3 = 1 over 8. 1 over 2 ±1 over 2 1 over 4 ±1 over 4

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  1. anonymous
    • one year ago
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    @ospreytriple

  2. anonymous
    • one year ago
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    You have\[x^3 = \frac{ 1 }{ 8 }\] If you can express \(\frac{1}{8}\) as a number raised to exponent 3, then you can simply equate the bases. Can you think of a number that, when cubed, equals 1\8 ?

  3. anonymous
    • one year ago
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    1/2 @ospreytriple

  4. anonymous
    • one year ago
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    b is incorrect because the plus and minus sign you dont use in power to the third

  5. anonymous
    • one year ago
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    Excellent. So\[x^3 = \left( \frac{ 1 }{ 2 } \right)^3\]When the exponents are the same, simply equate the bases. So\[x=?\]

  6. anonymous
    • one year ago
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    1/2 is the answer its not 1/2 plus minus sign

  7. anonymous
    • one year ago
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    @Marc1313 , please do not provide direct answers. It does not help the asker and it violates OpenStudy's Code of Conduct.

  8. anonymous
    • one year ago
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    i didnt provide direct answer @GIL.ojei did i was then one who said 1/2 plus minus sign so i was jsust saying that that is incorrect so idk what your talking about

  9. anonymous
    • one year ago
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    So sorry, @Marc1313 . My mistake, I thought you were a third party for a second. Your answer is correct. Well done.

  10. anonymous
    • one year ago
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    Okay. thank you.

  11. anonymous
    • one year ago
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    wait which one is the answer @ospreytriple

  12. anonymous
    • one year ago
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    We worked it down to\[x^3 = \left( \frac{ 1 }{ 2 } \right)^3\]Since exponents are the same we can equate just the bases, i.e.\[x=\frac{ 1 }{ 2 }\]See how that works?

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