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anonymous

  • one year ago

FAN+MEDAL PLEASE HELP! A group of 8 friends (5 girls and 3 boys) plans to watch a movie, but they have only 5 tickets. If they randomly decide who will watch the movie, what is the probability that there are at least 3 girls in the group that watch the movie?

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  1. anonymous
    • one year ago
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    @Hero

  2. anonymous
    • one year ago
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    @ganeshie8

  3. anonymous
    • one year ago
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    @goformit100

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    • one year ago
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    @Robert136

  6. anonymous
    • one year ago
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    First, the number of ways you can choose 5 people from 8 is given by 8!/(5!*3!) which is 8!/(5!*3!) There will be at least three girls except in the situation when all three boys are chosen. The number of ways can you choose 3 boys from 5 people is 5!/(3!*2!) which is 5!/(3!*2!) So the probability that there are at least 3 girls is (56 - 10)/56 or 46/56 = 0.821 I've assumed you know that the exclamation mark stands for "factorial". That is n! = n*(n-1)*(n-2)*....*2*1 Just in case you are uncertain about the above formulae, I'll illustrate all the possible ways of choosing 3 boys and 2 girls below. Each column below represents the tickets in the order in which they are drawn.

  7. anonymous
    • one year ago
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    there u go @alyssagoodm

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