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mathmath333
 one year ago
Counting question
mathmath333
 one year ago
Counting question

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mathmath333
 one year ago
Best ResponseYou've already chosen the best response.0dw:1440018965335:dw

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.0There are 8 letter A,B,C,D,E,F,G,H In a table in how many ways can the 8 letters be arranged such that A,B,C are only placed in column 1 and E,F are placed only in column 2.

phi
 one year ago
Best ResponseYou've already chosen the best response.1how many ways to put A,B,C in the first column?

phi
 one year ago
Best ResponseYou've already chosen the best response.1(and leave the last slot in column 1 empty)

phi
 one year ago
Best ResponseYou've already chosen the best response.1yes, I would 4 places to put A, 3 to put B, 2 to put C next , we fill the last slot , but we cant use A,B,C , E , F that leaves D,G,H so 4*3*2*3 to fill the first column

phi
 one year ago
Best ResponseYou've already chosen the best response.14*3 to fill the 2nd column with E and F that leaves 2 slots and 2 letters 4*3*2 so all together 4*3*2*3 * 4*3*2

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.0why didnt u add like 4*3*2*3+4*3*2

phi
 one year ago
Best ResponseYou've already chosen the best response.1we have 4*3*2*3 = 72 ways to fill the first column 1 say we had only 1 slot for column2 and we could put in A , B or C if we put in A in the second column, then we would have 72 patterns if we put in B we have the same 72 patterns but with a B , so different from the first set ditto for C in other words, if we have 6 patterns in the first column and 6 in the 2nd, we multiply to get the number of different patterns.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.04*3*2*4*3 *3! 4*3*2 for abc 4*3 for ef then 3! for the remaining

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1440023019651:dw
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