A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

mathmath333

  • one year ago

Counting question

  • This Question is Closed
  1. mathmath333
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1440018965335:dw|

  2. mathmath333
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    There are 8 letter A,B,C,D,E,F,G,H In a table in how many ways can the 8 letters be arranged such that A,B,C are only placed in column 1 and E,F are placed only in column 2.

  3. phi
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    how many ways to put A,B,C in the first column?

  4. phi
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    (and leave the last slot in column 1 empty)

  5. mathmath333
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    4*3*2

  6. phi
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    yes, I would 4 places to put A, 3 to put B, 2 to put C next , we fill the last slot , but we cant use A,B,C , E , F that leaves D,G,H so 4*3*2*3 to fill the first column

  7. mathmath333
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ok

  8. phi
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    4*3 to fill the 2nd column with E and F that leaves 2 slots and 2 letters 4*3*2 so all together 4*3*2*3 * 4*3*2

  9. mathmath333
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    why didnt u add like 4*3*2*3+4*3*2

  10. phi
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    we have 4*3*2*3 = 72 ways to fill the first column 1 say we had only 1 slot for column2 and we could put in A , B or C if we put in A in the second column, then we would have 72 patterns if we put in B we have the same 72 patterns but with a B , so different from the first set ditto for C in other words, if we have 6 patterns in the first column and 6 in the 2nd, we multiply to get the number of different patterns.

  11. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    4*3*2*4*3 *3! 4*3*2 for abc 4*3 for ef then 3! for the remaining

  12. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1440023019651:dw|

  13. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.