There are 5 cards with a picture of a rose and 1 card with a picture of a daisy. Olga keeps all the cards face down on the table with the pictures hidden and mixes them up. She then turns over one card and finds the picture of a rose on it. She removes this card from the table and turns over another card without looking. What is the probability that the card that Olga turns over has a rose on it? 1/5 4/6 4/5 5/6

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There are 5 cards with a picture of a rose and 1 card with a picture of a daisy. Olga keeps all the cards face down on the table with the pictures hidden and mixes them up. She then turns over one card and finds the picture of a rose on it. She removes this card from the table and turns over another card without looking. What is the probability that the card that Olga turns over has a rose on it? 1/5 4/6 4/5 5/6

Mathematics
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So, there are 6 cards in total. For the first card, what is the probability of flipping a rose?
so the answer is she removed a rose card already. how many cards total will be your bottom variable how many cards remaining have roses will be your top variable
would it be 5/6?

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Other answers:

no 4/5
There are 5 roses and 6 cards in total. So the probability of choosing a rose on the first flip is 5/6. OK with that?
OK
so my answer is 4/5 right?
Now, the first card is removed, so there remains 4 roses and 1 daisy left (a total of 5 cards). On this secon flip, what is the probability of flipping a rose?
5
you have removed a card already so that card no longer counts ie \[5r+1l=6total\] \[5r-1r=4r+1l=5t\] so 4r/5t
oh OK thank you!
To get your final answer, you multiply the two individual probabilities together.\[P_{A \text{ then }B} = P_A \times P_B\]

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