Given the functions a(x) = 3x − 12 and b(x) = x − 9, solve a[b(x)] and select the correct answer below. a[b(x)] = 3x2 − 21 a[b(x)] = 3x2 − 39 a[b(x)] = 3x − 21 a[b(x)] = 3x − 39

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Given the functions a(x) = 3x − 12 and b(x) = x − 9, solve a[b(x)] and select the correct answer below. a[b(x)] = 3x2 − 21 a[b(x)] = 3x2 − 39 a[b(x)] = 3x − 21 a[b(x)] = 3x − 39

Mathematics
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please help ill medal and fan if i dont fan you already
The easiest way to explain is with an example....say you're evaluating for x=2. Because it's asking for a(b(x)), you plug in the x value into b(x) first. Whatever answer you get, you plug that in for x in the a(x) function.

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ok??? :/
because they didn't give you a value for x, you have to plug in the entire b(x) function for every x value in the a(x) function. Once you've done that you simplify
ok what next??
so it'll look like this... a(b(x))=3(x-9)-12
oh ok so next it would be 3x - 27 - 12
???
perfect, combine like terms and you're done.
x = -39?
wait now divide
nope...you're not solving for anything. go back to what you had before...3x-27-12
3x = -39 x = -13
again, not solving for anything....so when you combine like terms that's just a fancy way of saying do all addition and subtraction you can. If you have 2x+3x-12 and you combine terms it would be 5x-12.
oh ok
so 3x-27-12...you can combine the -27 and the -12
again that would be -39
yup...put it with the first part of the equation and you have a(b(x))=3x-39
oh ok what now
that's it...in your original question it's the last choice in the list.
it's not set equal to anything so x is just a variable...it could be anything.
OH ITS D
YAYAYA YOUR AMAZING THANKS can you help with a couple more???
I'm a math/science teacher so I should know what I'm talking about :)
and sure, I have a little more time.

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