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anonymous

  • one year ago

Find the standard form of the equation of the parabola with a focus at (7, 0) and a directrix at x = -7.

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  1. anonymous
    • one year ago
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    lol this might be 12 grade work lol cuz i never heard of it

  2. anonymous
    • one year ago
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    its precalc @*ImaBeMe*

  3. anonymous
    • one year ago
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    do you know whats special about a focus and directrix

  4. anonymous
    • one year ago
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    kinda not really @dan915

  5. anonymous
    • one year ago
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    okay basically for focus if u fire any line at into the parabola it will reflect off into the focus

  6. anonymous
    • one year ago
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    ok @nanaruiz123

  7. anonymous
    • one year ago
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    |dw:1440020061995:dw|

  8. anonymous
    • one year ago
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    |dw:1440020159826:dw|

  9. anonymous
    • one year ago
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    like that all vertical lines that bounce off the parabola will reflect into the focus

  10. anonymous
    • one year ago
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    |dw:1440020223165:dw|

  11. anonymous
    • one year ago
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    do you understand the focus now?

  12. anonymous
    • one year ago
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    yes but is there an equation i cant use or something @dan915

  13. anonymous
    • one year ago
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    well u are gonna solve for that

  14. anonymous
    • one year ago
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    you need to know what a focus and directrix is to solve for it

  15. anonymous
    • one year ago
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    |dw:1440020416431:dw|

  16. anonymous
    • one year ago
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    the vertex has to be at 0,0 because it has to be in the middle of the directrix and the focus now you need some more points so you can solve for the whole parabola equation

  17. anonymous
    • one year ago
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    |dw:1440020622812:dw|

  18. anonymous
    • one year ago
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    |dw:1440020708157:dw|

  19. anonymous
    • one year ago
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    wait im confused? @dan915

  20. campbell_st
    • one year ago
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    here is an easy method that uses the focal length and the standard form in this case of \[4a(x - h) = (y - k)^2\] (h, k) is the focus and a is the focal length|dw:1440022451273:dw|

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