brodybarnes35
  • brodybarnes35
Given the functions f(x) = 7x + 13 and g(x) = x + 2, which of the following functions represents f[g(x)] correctly? f[g(x)] = 7x + 15 f[g(x)] = 7x + 27 f[g(x)] = 7x2 + 15 f[g(x)] = 7x2 + 27
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
brodybarnes35
  • brodybarnes35
@Hero @stacy.reed08
anonymous
  • anonymous
ok, same thing as the last one :)
brodybarnes35
  • brodybarnes35
ok so im guessing C!!??

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More answers

brodybarnes35
  • brodybarnes35
add like terms
anonymous
  • anonymous
don't guess, plug it in and work through one step at a time...
brodybarnes35
  • brodybarnes35
no i did lol
anonymous
  • anonymous
g(x)=x+2 so you plug in (x+2) for x in f(x)...what would that look like before you distribute it out and combine like terms?
brodybarnes35
  • brodybarnes35
7x + 13
brodybarnes35
  • brodybarnes35
7x
anonymous
  • anonymous
that's f(x)...take a step back...what would you do if it told you to evaluate f(x) for x=3?
brodybarnes35
  • brodybarnes35
oh 21
brodybarnes35
  • brodybarnes35
7(3)
anonymous
  • anonymous
perfect! you'd plug it in! but here's the thing...you don't have a value for x. you have (x+2), but it still works the same way. You plug it in to f(x) so you get 7(x+2)+13
anonymous
  • anonymous
so now's the time to use the distributive property and multiply it out.
brodybarnes35
  • brodybarnes35
oh ok so its D right i multiplied
brodybarnes35
  • brodybarnes35
i distributed not multiplied
anonymous
  • anonymous
go back :) I know it can be frustrating, but you can totally get this!
brodybarnes35
  • brodybarnes35
yikes i thought i got it right ://
anonymous
  • anonymous
do 7 times x and then 7 times 2
brodybarnes35
  • brodybarnes35
7x and 14
anonymous
  • anonymous
bingo! so now put it all back together...7x+14+13
brodybarnes35
  • brodybarnes35
7x + 27!!
anonymous
  • anonymous
which is what answer choice?
brodybarnes35
  • brodybarnes35
So B!
anonymous
  • anonymous
there it is! great work!
brodybarnes35
  • brodybarnes35
You're an amazing teacher thank you so much!!! :D
anonymous
  • anonymous
You are oh so welcome! Thank YOU for not giving up!
brodybarnes35
  • brodybarnes35
ill make sure to tag your from now on when i have a question thanks so much!! Have a wonderful day ma'am :))))
anonymous
  • anonymous
:) have a great evening!

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