On average, a commercial airplane burns about 4.0 × 103 mL of gasoline per second. There can be as many as 5 × 103 airplanes in the air in the United States at any given time.
About how many milliliters of gasoline are burned per minute by commercial airplanes in flight in the United States?
1.2 * 10^a mL
solve the exponet i think it is either 9 or 3, need help!
Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Not the answer you are looking for? Search for more explanations.
Okay, so I'm assuming based on the question that when you typed '103', you actually meant '10^3', which makes more sense in context.
So we know a commercial aircraft burns 4.0 x 10^3 mL/sec of gasoline. Twice as many commercial aircraft burn twice as much gasoline, so we need to multiply how much 1 airplane uses by the amount of airplanes in the sky. In this case, the problem tells us this is 5.0 x 10^3.
(4.0 x 10^3) x (5.0 * 10^3) = 20.0 * 10^6, which equals 2.0 * 10^7 mL/sec.
We may appear to be done here, but we need to be careful; the problem is asking us how much is burnt every MINUTE, not every second. A minute contains 60 seconds, so that means 60 times as much gasoline is burnt. 60 x (2.0 * 10^7) = 120.0 * 10^7, which equals 1.2 * 10^9 by scientific notation. Thus our answer is 1.2 * 10^9 mL/min of gasoline.
do u guys agree with @NathalyN ?
I'm just wondering why it is in the english section.... and not math.
http://www.regentsprep.org/regents/math/algtrig/ate8/exponentialequations.htm Go here to learn more about solving Exponential Equations.