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B. Use model 1 to determine the cost in 2000 of what cost $10,000 in 1975.

C= 952 (25)+15,162 or C= 952 (30)+15,162

C. Use model 2 to determine the cost in 2000 of what cost $10,000 in 1975.

what is model1,2?

The first picture has the equation for model 1 and 2.

okay, I didn't notice that pic :D..
wait solving...

Okay

if you put x=25 in the first equation, you get y which is the answer

38,287

i guess you did that way.... that should be correct.

and in the second equation what did you put?

I got 38,614

And both of them were wrong.. I have a similar problem pulled up now

hmmm.... i will ask @phi

is the answer 32000, just asking?

I think it was 32,202 but I cant see it any more.

@phi is here...
He is awesome....... dont worry @Destinyyyy

So I ignore 1975??? O.o

the formula we use says "x is years from 1980".
ok, then that is what we do.

for the first one you sub in 20 for x

34,202

ok

Is that the final answer?

it depends, do they want the exact number, or do they want you to round it to the nearest thousand?

It says round to the nearest thousand dollar as needed.

I know for part (a) you should round. (it is hard to read a graph very accurately)

Opps sorry read the wrong one. It says round to the nearest dollar as needed

then that is the answer (without the comma, probably)

Okay..What about C.?

Do the same thing?

x is still 20, but use a different equation

29,964

if you go by the graph, it looks like 32,000

Yes thats the answer for A.

I got a different number for part c

is your name destiny cuz my name is desteny just with an e insted of an i

15,964

can you show your work?

-2(20)^2 +1020 (20) +14364
-2(400)+ 2400 +14,364
15964

1020*20 is not 2400

Yes my name is Destiny.

oh cool

Opps guess I typed plus instead of multiply

Yes I just got that

So 33,964 is the final answer?

yes

Okay. Thank you!

if it does not have to be rounded...then yes

Good job in helping her, everyone..... :D