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anonymous
 one year ago
i need help with a few questions
anonymous
 one year ago
i need help with a few questions

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0just saying im only a 6th grader

Black_ninja123
 one year ago
Best ResponseYou've already chosen the best response.0What do you need help with?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ill put a attachment

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0dw:1440023993247:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1440024037929:dw

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0dw:1440024041423:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0If both numbers are divisible by each other then the LCM is less than the product if not then the LCM is the product

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0to add fractions you want to add " like terms" and that's the purpose of the LCM

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1440024105861:dw im not sure because i havent done this science the 4th grade

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0lmc stands for least common multiple

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0here you have thirds and fifths not like terms so you find the equivalent using the LCM so they will be equivalent parts

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0dw:1440024251206:dw

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0do you need me to relate it to real life example or do you remember how to add fractions now?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0im still not really sure

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0@joyraheb not exactly if one is a factor of the other then the LCM is less than the product

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0@rami2021 back to the example

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0after you find the LCM multiply each term by this number then all the denominator will be the same so you just simplify the numerator

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i got it now thx for explaining it to me

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0to find the LCM of 2 numbers consider the prime factors if you have any factors in both numbers only multiply once

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0dw:1440024751680:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@triciaal well if we are talking about fraction which i think what he is asking for its simply of the largest denominated is divisible by the other then no need to multiply both denom

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0That is what i meant in my previous comment i just think people will understand me directly when such question is asked

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0that's a better answer though not as complete as mine that tells what to multiply

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0" If both numbers are divisible by each other " this is confusing
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