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anonymous

  • one year ago

i need help with a few questions

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  1. anonymous
    • one year ago
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    Shoot

  2. anonymous
    • one year ago
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    ok

  3. anonymous
    • one year ago
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    just saying im only a 6th grader

  4. anonymous
    • one year ago
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    No prob

  5. Black_ninja123
    • one year ago
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    What do you need help with?

  6. anonymous
    • one year ago
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    ill put a attachment

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  7. triciaal
    • one year ago
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    |dw:1440023993247:dw|

  8. anonymous
    • one year ago
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    |dw:1440024037929:dw|

  9. triciaal
    • one year ago
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    |dw:1440024041423:dw|

  10. triciaal
    • one year ago
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    oh no

  11. anonymous
    • one year ago
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    If both numbers are divisible by each other then the LCM is less than the product if not then the LCM is the product

  12. triciaal
    • one year ago
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    to add fractions you want to add " like terms" and that's the purpose of the LCM

  13. anonymous
    • one year ago
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    |dw:1440024105861:dw| im not sure because i havent done this science the 4th grade

  14. anonymous
    • one year ago
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    opps i mean since

  15. anonymous
    • one year ago
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    lmc stands for least common multiple

  16. triciaal
    • one year ago
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    here you have thirds and fifths not like terms so you find the equivalent using the LCM so they will be equivalent parts

  17. anonymous
    • one year ago
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    ok

  18. triciaal
    • one year ago
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    |dw:1440024251206:dw|

  19. triciaal
    • one year ago
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    do you need me to relate it to real life example or do you remember how to add fractions now?

  20. anonymous
    • one year ago
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    im still not really sure

  21. triciaal
    • one year ago
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    @joyraheb not exactly if one is a factor of the other then the LCM is less than the product

  22. triciaal
    • one year ago
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    @rami2021 back to the example

  23. triciaal
    • one year ago
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    after you find the LCM multiply each term by this number then all the denominator will be the same so you just simplify the numerator

  24. anonymous
    • one year ago
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    i got it now thx for explaining it to me

  25. triciaal
    • one year ago
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    to find the LCM of 2 numbers consider the prime factors if you have any factors in both numbers only multiply once

  26. triciaal
    • one year ago
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    |dw:1440024751680:dw|

  27. anonymous
    • one year ago
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    @triciaal well if we are talking about fraction which i think what he is asking for its simply of the largest denominated is divisible by the other then no need to multiply both denom

  28. anonymous
    • one year ago
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    That is what i meant in my previous comment i just think people will understand me directly when such question is asked

  29. triciaal
    • one year ago
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    that's a better answer though not as complete as mine that tells what to multiply

  30. triciaal
    • one year ago
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    " If both numbers are divisible by each other " this is confusing

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