At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
just saying im only a 6th grader
What do you need help with?
If both numbers are divisible by each other then the LCM is less than the product if not then the LCM is the product
to add fractions you want to add " like terms" and that's the purpose of the LCM
|dw:1440024105861:dw| im not sure because i havent done this science the 4th grade
opps i mean since
lmc stands for least common multiple
here you have thirds and fifths not like terms so you find the equivalent using the LCM so they will be equivalent parts
do you need me to relate it to real life example or do you remember how to add fractions now?
im still not really sure
@joyraheb not exactly if one is a factor of the other then the LCM is less than the product
@rami2021 back to the example
after you find the LCM multiply each term by this number then all the denominator will be the same so you just simplify the numerator
i got it now thx for explaining it to me
to find the LCM of 2 numbers consider the prime factors if you have any factors in both numbers only multiply once
@triciaal well if we are talking about fraction which i think what he is asking for its simply of the largest denominated is divisible by the other then no need to multiply both denom
That is what i meant in my previous comment i just think people will understand me directly when such question is asked
that's a better answer though not as complete as mine that tells what to multiply
" If both numbers are divisible by each other " this is confusing