anonymous
  • anonymous
i need help with a few questions
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
Shoot
anonymous
  • anonymous
ok
anonymous
  • anonymous
just saying im only a 6th grader

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anonymous
  • anonymous
No prob
Black_ninja123
  • Black_ninja123
What do you need help with?
anonymous
  • anonymous
ill put a attachment
1 Attachment
triciaal
  • triciaal
|dw:1440023993247:dw|
anonymous
  • anonymous
|dw:1440024037929:dw|
triciaal
  • triciaal
|dw:1440024041423:dw|
triciaal
  • triciaal
oh no
anonymous
  • anonymous
If both numbers are divisible by each other then the LCM is less than the product if not then the LCM is the product
triciaal
  • triciaal
to add fractions you want to add " like terms" and that's the purpose of the LCM
anonymous
  • anonymous
|dw:1440024105861:dw| im not sure because i havent done this science the 4th grade
anonymous
  • anonymous
opps i mean since
anonymous
  • anonymous
lmc stands for least common multiple
triciaal
  • triciaal
here you have thirds and fifths not like terms so you find the equivalent using the LCM so they will be equivalent parts
anonymous
  • anonymous
ok
triciaal
  • triciaal
|dw:1440024251206:dw|
triciaal
  • triciaal
do you need me to relate it to real life example or do you remember how to add fractions now?
anonymous
  • anonymous
im still not really sure
triciaal
  • triciaal
@joyraheb not exactly if one is a factor of the other then the LCM is less than the product
triciaal
  • triciaal
@rami2021 back to the example
triciaal
  • triciaal
after you find the LCM multiply each term by this number then all the denominator will be the same so you just simplify the numerator
anonymous
  • anonymous
i got it now thx for explaining it to me
triciaal
  • triciaal
to find the LCM of 2 numbers consider the prime factors if you have any factors in both numbers only multiply once
triciaal
  • triciaal
|dw:1440024751680:dw|
anonymous
  • anonymous
@triciaal well if we are talking about fraction which i think what he is asking for its simply of the largest denominated is divisible by the other then no need to multiply both denom
anonymous
  • anonymous
That is what i meant in my previous comment i just think people will understand me directly when such question is asked
triciaal
  • triciaal
that's a better answer though not as complete as mine that tells what to multiply
triciaal
  • triciaal
" If both numbers are divisible by each other " this is confusing

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