i need help with a few questions

- anonymous

i need help with a few questions

- Stacey Warren - Expert brainly.com

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- chestercat

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- anonymous

Shoot

- anonymous

ok

- anonymous

just saying im only a 6th grader

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## More answers

- anonymous

No prob

- Black_ninja123

What do you need help with?

- anonymous

ill put a attachment

##### 1 Attachment

- triciaal

|dw:1440023993247:dw|

- anonymous

|dw:1440024037929:dw|

- triciaal

|dw:1440024041423:dw|

- triciaal

oh no

- anonymous

If both numbers are divisible by each other then the LCM is less than the product if not then the LCM is the product

- triciaal

to add fractions you want to add " like terms" and that's the purpose of the LCM

- anonymous

|dw:1440024105861:dw| im not sure because i havent done this science the 4th grade

- anonymous

opps i mean since

- anonymous

lmc stands for least common multiple

- triciaal

here you have thirds and fifths not like terms so you find the equivalent using the LCM so they will be equivalent parts

- anonymous

ok

- triciaal

|dw:1440024251206:dw|

- triciaal

do you need me to relate it to real life example or do you remember how to add fractions now?

- anonymous

im still not really sure

- triciaal

@joyraheb not exactly if one is a factor of the other then the LCM is less than the product

- triciaal

@rami2021 back to the example

- triciaal

after you find the LCM multiply each term by this number then all the denominator will be the same so you just simplify the numerator

- anonymous

i got it now thx for explaining it to me

- triciaal

to find the LCM of 2 numbers consider the prime factors if you have any factors in both numbers only multiply once

- triciaal

|dw:1440024751680:dw|

- anonymous

@triciaal well if we are talking about fraction which i think what he is asking for its simply of the largest denominated is divisible by the other then no need to multiply both denom

- anonymous

That is what i meant in my previous comment i just think people will understand me directly when such question is asked

- triciaal

that's a better answer though not as complete as mine that tells what to multiply

- triciaal

" If both numbers are divisible by each other " this is confusing

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