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## anonymous one year ago .

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1. jim_thompson5910

is it $\Large \sqrt{x-1}$ OR is it $\Large \sqrt{x}-1$ ??

2. anonymous

it is the first one the line covers both the x and 1

3. anonymous

i just didn't know how to show that on here

4. jim_thompson5910

that's ok. thanks for clarifying

5. anonymous

yw

6. jim_thompson5910

so the basic rule is that if you have some function f(x), if you replaced x with x-h then the entire graph shifts h units to the right (if h is positive) for example $\Large f(x) = \sqrt{x}$ $\Large f(\color{red}{x}) = \sqrt{\color{red}{x}}$ $\Large f(\color{red}{x-7}) = \sqrt{\color{red}{x-7}} \ \text{shift 7 units right}$

7. anonymous

in this case it would shift one unit to the right?

8. jim_thompson5910

if h was negative, then the shift would go left eg: $\Large f(x) = \sqrt{x}$ $\Large f(\color{red}{x}) = \sqrt{\color{red}{x}}$ $\Large f(\color{red}{x-(-12)}) = \sqrt{\color{red}{x-(-12)}} \ \text{shift 12 units left}$ $\Large f(\color{red}{x+12}) = \sqrt{\color{red}{x+12}} \ \text{shift 12 units left}$

9. jim_thompson5910

correct, in this problem, the x-1 under the root means "shift the parent graph 1 unit to the right"

10. jim_thompson5910

I recommend you compare the two graphs using something like desmos https://www.desmos.com/calculator

11. anonymous

so I was right then

12. anonymous

@jim_thompson5910 thanks for going over that with me. It's appreciated :)

13. jim_thompson5910

you're welcome

14. anonymous

@jim_thompson5910 I have another question, if it said x+7 (kinda like what you wrote but addition) would it be like shift the unites to the left?

15. jim_thompson5910

yep the x+7 under the root would mean "shift 7 units left"

16. anonymous

okay cool. I get these now, thank you. And thanks for the graph website :D

17. jim_thompson5910

sure thing. I'm glad to be of help

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