anonymous
  • anonymous
Use the given graph to determine the limit, if it exists. https://i.gyazo.com/254eea10a80f60d83172f2fdb9ca3a99.png
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
\(\lim_{x \rightarrow 2^-}f(x)= \) the y-value of f(x) left of 2 \(\lim_{x \rightarrow 2^+}f(x)= \) the y-value of f(x) right of 2
anonymous
  • anonymous
im sorry my computer doesnt support latex
anonymous
  • anonymous
ok i wrote it out better on paper

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anonymous
  • anonymous
do you mind typing out the function so i can make sure i wrote it out right?
anonymous
  • anonymous
I don't really have a function typed out, and you don't really need it. The left limit is asking you as you go along the lines toward 2 from the left, what is the y-value you end up at? The right limit is asking the same thing about approaching 2 from the right|dw:1440033130819:dw|
anonymous
  • anonymous
in other words, what's the y-coordinates of the open circles?
anonymous
  • anonymous
4 and -2
anonymous
  • anonymous
right. Since the left limit is 4 and the right limit is -2, the "overall" limit approaching 2 doesn't exist
anonymous
  • anonymous
For the limit approaching 2 to exist, the left and right limits must be equal
anonymous
  • anonymous
oh ok cool. Do you mind helping me with one more?
anonymous
  • anonymous
ok
anonymous
  • anonymous
https://i.gyazo.com/be766039a28ceb425f72a6c9f1fe6c08.png
anonymous
  • anonymous
ok so this one's asking for a left limit only. so use the line on the left.
anonymous
  • anonymous
so its the y coordinates of the open circle of the left line?
anonymous
  • anonymous
yes
anonymous
  • anonymous
oh ok. you know what it was. the answer was 1.3. i thinking it was just 1. But thanks for the help.
anonymous
  • anonymous
you're welcome

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