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anonymous

  • one year ago

Use the given graph to determine the limit, if it exists. https://i.gyazo.com/254eea10a80f60d83172f2fdb9ca3a99.png

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  1. anonymous
    • one year ago
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    \(\lim_{x \rightarrow 2^-}f(x)= \) the y-value of f(x) left of 2 \(\lim_{x \rightarrow 2^+}f(x)= \) the y-value of f(x) right of 2

  2. anonymous
    • one year ago
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    im sorry my computer doesnt support latex

  3. anonymous
    • one year ago
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    ok i wrote it out better on paper

  4. anonymous
    • one year ago
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    do you mind typing out the function so i can make sure i wrote it out right?

  5. anonymous
    • one year ago
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    I don't really have a function typed out, and you don't really need it. The left limit is asking you as you go along the lines toward 2 from the left, what is the y-value you end up at? The right limit is asking the same thing about approaching 2 from the right|dw:1440033130819:dw|

  6. anonymous
    • one year ago
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    in other words, what's the y-coordinates of the open circles?

  7. anonymous
    • one year ago
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    4 and -2

  8. anonymous
    • one year ago
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    right. Since the left limit is 4 and the right limit is -2, the "overall" limit approaching 2 doesn't exist

  9. anonymous
    • one year ago
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    For the limit approaching 2 to exist, the left and right limits must be equal

  10. anonymous
    • one year ago
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    oh ok cool. Do you mind helping me with one more?

  11. anonymous
    • one year ago
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    ok

  12. anonymous
    • one year ago
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    https://i.gyazo.com/be766039a28ceb425f72a6c9f1fe6c08.png

  13. anonymous
    • one year ago
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    ok so this one's asking for a left limit only. so use the line on the left.

  14. anonymous
    • one year ago
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    so its the y coordinates of the open circle of the left line?

  15. anonymous
    • one year ago
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    yes

  16. anonymous
    • one year ago
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    oh ok. you know what it was. the answer was 1.3. i thinking it was just 1. But thanks for the help.

  17. anonymous
    • one year ago
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    you're welcome

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