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- anonymous

Use the given graph to determine the limit, if it exists.
https://i.gyazo.com/254eea10a80f60d83172f2fdb9ca3a99.png

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- anonymous

- schrodinger

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- anonymous

\(\lim_{x \rightarrow 2^-}f(x)= \) the y-value of f(x) left of 2
\(\lim_{x \rightarrow 2^+}f(x)= \) the y-value of f(x) right of 2

- anonymous

im sorry my computer doesnt support latex

- anonymous

ok i wrote it out better on paper

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- anonymous

do you mind typing out the function so i can make sure i wrote it out right?

- anonymous

I don't really have a function typed out, and you don't really need it. The left limit is asking you as you go along the lines toward 2 from the left, what is the y-value you end up at? The right limit is asking the same thing about approaching 2 from the right|dw:1440033130819:dw|

- anonymous

in other words, what's the y-coordinates of the open circles?

- anonymous

4 and -2

- anonymous

right. Since the left limit is 4 and the right limit is -2, the "overall" limit approaching 2 doesn't exist

- anonymous

For the limit approaching 2 to exist, the left and right limits must be equal

- anonymous

oh ok cool. Do you mind helping me with one more?

- anonymous

ok

- anonymous

https://i.gyazo.com/be766039a28ceb425f72a6c9f1fe6c08.png

- anonymous

ok so this one's asking for a left limit only. so use the line on the left.

- anonymous

so its the y coordinates of the open circle of the left line?

- anonymous

yes

- anonymous

oh ok. you know what it was. the answer was 1.3. i thinking it was just 1. But thanks for the help.

- anonymous

you're welcome

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