anonymous one year ago Use the given graph to determine the limit, if it exists. https://i.gyazo.com/254eea10a80f60d83172f2fdb9ca3a99.png

1. anonymous

$$\lim_{x \rightarrow 2^-}f(x)=$$ the y-value of f(x) left of 2 $$\lim_{x \rightarrow 2^+}f(x)=$$ the y-value of f(x) right of 2

2. anonymous

im sorry my computer doesnt support latex

3. anonymous

ok i wrote it out better on paper

4. anonymous

do you mind typing out the function so i can make sure i wrote it out right?

5. anonymous

I don't really have a function typed out, and you don't really need it. The left limit is asking you as you go along the lines toward 2 from the left, what is the y-value you end up at? The right limit is asking the same thing about approaching 2 from the right|dw:1440033130819:dw|

6. anonymous

in other words, what's the y-coordinates of the open circles?

7. anonymous

4 and -2

8. anonymous

right. Since the left limit is 4 and the right limit is -2, the "overall" limit approaching 2 doesn't exist

9. anonymous

For the limit approaching 2 to exist, the left and right limits must be equal

10. anonymous

oh ok cool. Do you mind helping me with one more?

11. anonymous

ok

12. anonymous
13. anonymous

ok so this one's asking for a left limit only. so use the line on the left.

14. anonymous

so its the y coordinates of the open circle of the left line?

15. anonymous

yes

16. anonymous

oh ok. you know what it was. the answer was 1.3. i thinking it was just 1. But thanks for the help.

17. anonymous

you're welcome