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anonymous
 one year ago
What is the limit of
(x)÷((1/1+x)−1)
as x approaches 0?
anonymous
 one year ago
What is the limit of (x)÷((1/1+x)−1) as x approaches 0?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\large \lim_{x \rightarrow 0} \frac{ x }{ \left( \frac{ 1 }{ 1+x }1 \right) }\] this?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Lets start off by simplifying the denominator you can use the following \[\frac{ a }{ b } \pm \frac{ c }{ d } \implies \frac{ ad \pm bc }{ bd }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Go ahead and see what you get

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So then would the denominator be \[(11+x)/(1+x)\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0wait, the first part should be 11x I think.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\huge \lim_{x \rightarrow 0} \frac{ x }{ \left( \frac{ 11(1+x) }{ 1+x } \right) } = \lim_{x \rightarrow 0}\frac{ x }{ \left( \frac{ 11x }{ 1+x } \right) }\] correct?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yeah. And then I just use the reciprocal of the denominator and plug in the 0, and I get 1?
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