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anonymous
 one year ago
For every point on the graph of F(x), there is a point on the graph of F 1(x) with exactly the same coordinates.
A. True
B. False
anonymous
 one year ago
For every point on the graph of F(x), there is a point on the graph of F 1(x) with exactly the same coordinates. A. True B. False

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0would this be false because since the second F(x) is negative wouldn't that make the numbers negative and not "exactly the same"

triciaal
 one year ago
Best ResponseYou've already chosen the best response.1I think what you have would be correct for f(x) but this is the inverse of the function f 1 where x and y are switched and would make it true.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so then it would be true not false?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0`For every point on the graph of F(x), there is a point on the graph of F 1(x) with exactly the same coordinates.` this basically implies that f(x) and its inverse is the same graph. That is only true for f(x) = x and things like f(x) = 1/x. It's not true for any random f(x) function

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0is that what triciaal said incorrect?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0what do you mean?
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