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anonymous

  • one year ago

HELP !!!! im soo tired

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  1. anonymous
    • one year ago
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    U dont need help

  2. anonymous
    • one year ago
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  3. anonymous
    • one year ago
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    Tht shii confusing oml

  4. anonymous
    • one year ago
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    lol fr

  5. anonymous
    • one year ago
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    ima ask my cousin xD

  6. anonymous
    • one year ago
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    lol who dat

  7. anonymous
    • one year ago
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    He in 11th

  8. anonymous
    • one year ago
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    Ok kewl

  9. anonymous
    • one year ago
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    he said he dont know either

  10. anonymous
    • one year ago
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    ok lol

  11. campbell_st
    • one year ago
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    on... so Gary has 10 of 50 tickets so the P(Gary WIn) = 10/50 so if he wins 1st prize, how many tickets does he still have and how many tickets are still in the draw..?

  12. campbell_st
    • one year ago
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    The problem is simply a case of P(win, Win) = P(win1st) x P(win 2nd)

  13. anonymous
    • one year ago
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    ummmmm lol idk dang bruuuh thiis stuuf dawg on HARD!!!

  14. campbell_st
    • one year ago
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    so any ideas on how many tickets you have in the 2nd draw..? and how many tickets are left in the draw...?

  15. anonymous
    • one year ago
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    so ima take a wild guest and say 50 again ?????

  16. campbell_st
    • one year ago
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    great... so how many tickets does Gary have in the draw for the 2nd prize..?

  17. anonymous
    • one year ago
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    uhhhhhh 40 my brothua lol

  18. campbell_st
    • one year ago
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    no wonder you're tired, that is not even close..

  19. anonymous
    • one year ago
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    LOL!!!

  20. anonymous
    • one year ago
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    @campbell_st HELPPPPP

  21. campbell_st
    • one year ago
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    so Gary has 10 tickets.... is that ok..?

  22. anonymous
    • one year ago
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    yeah

  23. campbell_st
    • one year ago
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    P(1st Prize) = 10/50 or 1/5 P(2nd Prize) = 10/50 or 1/5 P(1st, 2nd) = 1/5 * 1/5

  24. anonymous
    • one year ago
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    ok what i do next

  25. anonymous
    • one year ago
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    @campbell_st

  26. campbell_st
    • one year ago
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    just multiply the fractions \[P(1st, 2nd) = \frac{1}{5} \times \frac{1}{5}\]

  27. anonymous
    • one year ago
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    and then i find tha percent and go my butt to bed lol

  28. campbell_st
    • one year ago
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    exactly

  29. anonymous
    • one year ago
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    Ok im gonna do that then u can see if im right plz

  30. anonymous
    • one year ago
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    @campbell_st i got 1 over 25 =1/25

  31. campbell_st
    • one year ago
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    correct as a fraction or 4%

  32. anonymous
    • one year ago
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    so is 0.04

  33. campbell_st
    • one year ago
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    correct...

  34. anonymous
    • one year ago
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    THANK CHU

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