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anonymous
 one year ago
I wonder if the Prof is correct in Lecture 2 at minute 8:19 where he said that the 3rd pivot is 5. I think that it is 3
anonymous
 one year ago
I wonder if the Prof is correct in Lecture 2 at minute 8:19 where he said that the 3rd pivot is 5. I think that it is 3

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The matrix after the first step of elimination looks like: \[\left[\begin{matrix}1 & 2 & 1\\ 0 & 2 & 2\\ 0 & 4 & 1\end{matrix}\right]\] We want to eliminate element 32 (that is 4). To do that, we multiply second row by 2 (to get 4 in 22 position): \[\left[\begin{matrix}1 & 2 & 1\\ 0 & 4 & 4\\ 0 & 4 & 1\end{matrix}\right]\] Finally, we subtract second line from the third: \[\left[\begin{matrix}1 & 2 & 1\\ 0 & 2 & 2\\ 00 & 44 & 1(4)\end{matrix}\right] =\left[\begin{matrix}1 & 2 & 1\\ 0 & 2 & 2\\ 0& 0& 5\end{matrix}\right]. \]
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