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anonymous

  • one year ago

4 sinx/cosx - 1/cos^2x=0 How would i simplify this to: 4sinxcosx=1

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  1. anonymous
    • one year ago
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    pls help

  2. anonymous
    • one year ago
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    \[\frac{ 4 \sin x }{ \cos x }-\frac{ 1 }{ \cos^2 x }=0\] is that your question?

  3. anonymous
    • one year ago
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    the 4 is seperated from sin/cos

  4. anonymous
    • one year ago
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    4(sinx/cosx)

  5. anonymous
    • one year ago
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    i typed in the question wrong sorry

  6. anonymous
    • one year ago
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    simplify it to 4(sinx)(cosx)=1

  7. dessyj1
    • one year ago
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    |dw:1440043157388:dw|

  8. anonymous
    • one year ago
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    please rewrite your question. @dijko

  9. anonymous
    • one year ago
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    ill take a picture

  10. anonymous
    • one year ago
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    https://gyazo.com/c687c7f60971a277f13584567a6555b0

  11. anonymous
    • one year ago
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    and then simplify to https://gyazo.com/c86ac642c02271fc20427f857713aafd

  12. dessyj1
    • one year ago
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    |dw:1440043215468:dw|

  13. dessyj1
    • one year ago
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    You get \[4\sin(x)\cos(x) =1\]

  14. anonymous
    • one year ago
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    thank you

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