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anonymous

  • one year ago

chemistry help!!! I have no idea how to name this please help.

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  1. anonymous
    • one year ago
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    @abhisar @abb0t @vocaloid @arronq

  2. anonymous
    • one year ago
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    Is this correct? I'm trying but I'm really not sure how.

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  3. Rushwr
    • one year ago
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    The first thing there are no triple bonds found. Only double bond is found so alkenes are found.

  4. anonymous
    • one year ago
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    Okay so it's an alkenes and ends in -ene ? @rushwer

  5. Rushwr
    • one year ago
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    Since that is an alkene and no other groups are found start numbering from that carbon. Find the longest carbon chain.

  6. Rushwr
    • one year ago
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    yep !

  7. Rushwr
    • one year ago
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    u better sort the steps and write it in ur words.

  8. anonymous
    • one year ago
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    Okay so seven carbons 1 heptene?

  9. Rushwr
    • one year ago
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    yep !

  10. anonymous
    • one year ago
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    And then is it 5-ethyl

  11. Abhisar
    • one year ago
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    |dw:1440043724082:dw|

  12. anonymous
    • one year ago
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    Now I'm confused.

  13. Rushwr
    • one year ago
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    @Abhisar But we have to go for the longest carbon chain !

  14. Abhisar
    • one year ago
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    Oops, I forgot that lol !

  15. anonymous
    • one year ago
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    What do I use to name the carbon branch 4-?

  16. Rushwr
    • one year ago
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    So I got 4-ethyl-1-heptene

  17. anonymous
    • one year ago
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    Wait so it's 7 carbons not 6?

  18. Rushwr
    • one year ago
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    yep 7 carbons.

  19. anonymous
    • one year ago
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    Okay so is this right?

  20. anonymous
    • one year ago
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    ?

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  21. Abhisar
    • one year ago
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    |dw:1440044064966:dw|

  22. anonymous
    • one year ago
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    Plecase Let Me know if I'm doing it right it's my last question.

  23. anonymous
    • one year ago
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    @abhisar @rushwer

  24. Abhisar
    • one year ago
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    yne is used for triple bond, ene for double bond.

  25. Abhisar
    • one year ago
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    Ethyl is at 4th carbon not at 5th carbon.

  26. Rushwr
    • one year ago
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    I would say. Identify the double bond . (identify the compound is an alkene) Number the main chain having the highest number of carbons which also contains all the double bonds. The C=C double bond should be given priority when numbering the main chain. Since the double bond acts as the main functional group in this numbering should be done in such manner where the lowest possible number is given to the C=C double bond / After numbering the main chain identify the side chain alkyl groups. I'm not sure if I missed anythn ! @Abhisar I'm baad in writting stuff step wisely. !!! just add the missing parts. :)

  27. anonymous
    • one year ago
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    Thanks so much

  28. Rushwr
    • one year ago
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    Anytym :)

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