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anonymous
 one year ago
Algebra 2 help would be greatly appreciated!
anonymous
 one year ago
Algebra 2 help would be greatly appreciated!

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[3^{2x}15(3^{x})+56=0\]

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2Hey so what's it asking

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.2substitute 3^x as a and solve the equation as a quadratic equation

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.2do you need more explanation ?i mean can do it on your own

madhu.mukherjee.946
 one year ago
Best ResponseYou've already chosen the best response.2@science00000 ??

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can i multiply the 15 and 3^x ???

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2No but you can simplify it 5(3^x+1)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0don't seem to be quite understanding this :/

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2You have to know your exponent rules, 5 x 3 = 15, so we have 5(3)(3^x) you can only do this with like bases so we have \[3^{x+1}\]

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2So here is the general rule \[x^mx^n = x^{m+n}\]

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2You can factor this I suppose

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2Yes, factoring should work

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2factoring you should end up with \[(3^x8)(3^x7)=0\] as we are treating 3^x as a, also suggested above

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ohh this makes a little more sense now!

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.27 x  8 = 56 7+8=15

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1\[\large 3^{2x}15(3^{x})+56=0\] \[\large (\color{red}{3^{x}})^215(\color{red}{3^{x}})+56=0\] let \(t=\color{red}{3^{x}}\) \[\large (\color{red}t{})^215(\color{red}{t})+56=0\] you knw how to handle a quadratic

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes!! Thanks everyone for helping! Really appreciate it.

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2You can solve for x now, it involves logarithms, you know how to do that right? \[3^x  7 = 0\] set it to 0 and solve for x for both

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yeah of course. Thanks again everyone!
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