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what is \(f(1)\)?
but what is f(1)?
-4x + 7?
do you understand what \(f(1)\) means?
it means put a \(1\) in the function \(f\) where ever you see an \(x\).
no this is in a packet about composition of functions. Just problems to work out. I'm trying to look online.
not much explaination
but before you can understand composition of functions, you must understand a function.
for the function \(f(x) = -4x+7\) we have \(f(1) = -4*1+7=3\). Does this make sense?
ok now then, what is \(g(3)\)?
g(3) is we put a 3 in the function where the x is @zzr0ck3r
and it would look like g(3) = 2*3 - 6 I think?
which is 0
Hey, so the notation just implies g(f(1)) it's probably simpler to find g(f(x)) first this just means plug the function f(x) wherever there is an x in function g(x). Try that out :)
Or we can do it the way @zzr0ck3r what ever you are comfortable with!
i'm not sure how I would right that
No worries, f(x) = -4x+7 and g(x) = 2x-6 so we take function f(x) and plug it in g(x) \[g(f(x)) = 2(-4x+7)-6\]
Now you can find g(f(1)) by plugging in 1 where the x is and evaluating
Does this make sense? It can be a bit confusing haha.
so it would be 0 then?
It makes sense though a bit complicated. It's something I'm gonna have to really ingrain in my head.
@Astrophysics how would I solve it the way @zzr0ck3r did it? I wasn't sure what to do after he left.
Yup, 0 sounds good!
Thanks for helping me. You're awesome :)
Ok so with zz's method you found what f(1) was which is 3 correct
Then we just take f(1) and plug that in g(x) for g(f(1)) = 2(3)-6 = 0 :)
Either way works :P
oh I see. Both of you guys gave me good ways. Thank you again