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anonymous
 one year ago
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anonymous
 one year ago
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zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.1do you understand what \(f(1)\) means?

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.1it means put a \(1\) in the function \(f\) where ever you see an \(x\).

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no this is in a packet about composition of functions. Just problems to work out. I'm trying to look online.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0not much explaination

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.1but before you can understand composition of functions, you must understand a function.

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.1for the function \(f(x) = 4x+7\) we have \(f(1) = 4*1+7=3\). Does this make sense?

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.1ok now then, what is \(g(3)\)?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0g(3) is we put a 3 in the function where the x is @zzr0ck3r

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and it would look like g(3) = 2*3  6 I think?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Hey, so the notation just implies g(f(1)) it's probably simpler to find g(f(x)) first this just means plug the function f(x) wherever there is an x in function g(x). Try that out :)

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Or we can do it the way @zzr0ck3r what ever you are comfortable with!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i'm not sure how I would right that

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1No worries, f(x) = 4x+7 and g(x) = 2x6 so we take function f(x) and plug it in g(x) \[g(f(x)) = 2(4x+7)6\]

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Now you can find g(f(1)) by plugging in 1 where the x is and evaluating

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Does this make sense? It can be a bit confusing haha.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so it would be 0 then?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It makes sense though a bit complicated. It's something I'm gonna have to really ingrain in my head.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Astrophysics how would I solve it the way @zzr0ck3r did it? I wasn't sure what to do after he left.

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Yup, 0 sounds good!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thanks for helping me. You're awesome :)

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Ok so with zz's method you found what f(1) was which is 3 correct

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Then we just take f(1) and plug that in g(x) for g(f(1)) = 2(3)6 = 0 :)

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Either way works :P

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh I see. Both of you guys gave me good ways. Thank you again
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