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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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their all negative options. I just didn't notice there weren't there sorry.
replaced x with -4
isn't it g(x)*f(x)*(-4)

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are you familiar with these?
actually what i hav studied is that f(x) or g(x) can be written as f or g and f'g is f multiplied g
I think there's a few ways you can actually do it.
there is also braces for (f'g) separating it from (-4)
those ways can change the entire ans. actually!
yeah
Here's the question is \((g\circ f)(x)\) right?
yeah
Here's the thing: \[(g\circ f)(x)=g\left( f(x)\right)\\ gf(x)=g(x)\times f(x) \] right?
that circle between g and f means g "of" f
Still confused? It's the same as before g(f(4))
Same sort of question
I did g(f(-4)) = 3(4x+7)-5 but that's wrong
so now I'm going through everything again
That's g(f(x)), you're on the right track g(x) = 3x-5 and f(x) = 4x+7 g(f(x)) = 3(4x+7)-5 for g(f(1)) we plug in 1 now where the x is. g(f(1)) = 3[4(1)+7]-5
oh I was doing -4 but I do 1 I guess.
Oh oops it's -4
oh
g(f(-4)) = 3[4(-4)+7]-5
You're doing it right then, why doubt yourself? :P
The other people helping me were showing me different things so I just assumed I was wrong. I was feeling really confident about it actually. Anyways I was right and the answer is -32.
Yay :)
!!

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