A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • one year ago

.

  • This Question is Closed
  1. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    their all negative options. I just didn't notice there weren't there sorry.

  2. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    replaced x with -4

  3. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    isn't it g(x)*f(x)*(-4)

  4. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    are you familiar with these?

  5. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    actually what i hav studied is that f(x) or g(x) can be written as f or g and f'g is f multiplied g

  6. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I think there's a few ways you can actually do it.

  7. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    there is also braces for (f'g) separating it from (-4)

  8. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @dan915 @amilapsn

  9. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    those ways can change the entire ans. actually!

  10. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @nincompoop

  11. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yeah

  12. amilapsn
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Here's the question is \((g\circ f)(x)\) right?

  13. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yeah

  14. amilapsn
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Here's the thing: \[(g\circ f)(x)=g\left( f(x)\right)\\ gf(x)=g(x)\times f(x) \] right?

  15. amilapsn
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    that circle between g and f means g "of" f

  16. Astrophysics
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Still confused? It's the same as before g(f(4))

  17. Astrophysics
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Same sort of question

  18. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I did g(f(-4)) = 3(4x+7)-5 but that's wrong

  19. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so now I'm going through everything again

  20. Astrophysics
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    That's g(f(x)), you're on the right track g(x) = 3x-5 and f(x) = 4x+7 g(f(x)) = 3(4x+7)-5 for g(f(1)) we plug in 1 now where the x is. g(f(1)) = 3[4(1)+7]-5

  21. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    oh I was doing -4 but I do 1 I guess.

  22. Astrophysics
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Oh oops it's -4

  23. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    oh

  24. Astrophysics
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    g(f(-4)) = 3[4(-4)+7]-5

  25. Astrophysics
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    You're doing it right then, why doubt yourself? :P

  26. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    The other people helping me were showing me different things so I just assumed I was wrong. I was feeling really confident about it actually. Anyways I was right and the answer is -32.

  27. Astrophysics
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Yay :)

  28. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    !!

  29. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.