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midhun.madhu1987
 one year ago
Someone Please help me regarding this question...I tried to prove it, but was not successful...
midhun.madhu1987
 one year ago
Someone Please help me regarding this question...I tried to prove it, but was not successful...

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midhun.madhu1987
 one year ago
Best ResponseYou've already chosen the best response.0Please note that: y1 = First Derivative y2 = Second Derivative

imqwerty
 one year ago
Best ResponseYou've already chosen the best response.2after differentiation y1 =e^arctan(x)/(x^2 +1) y2=[e^arctan(x) (2x+1)]/(x^2 +1)^2

imqwerty
 one year ago
Best ResponseYou've already chosen the best response.2lets call e^arctan(x)=a so we have y1=a/(x^2 +1) y2=[(a)(2x+1)]/(x^2+1)^2

imqwerty
 one year ago
Best ResponseYou've already chosen the best response.2it would be long if we put the values of y1,y2 ad y in the equation so lets think of a shorter method...

midhun.madhu1987
 one year ago
Best ResponseYou've already chosen the best response.0I am so sorrry... Since I am at the office now.. wont be able to look at it... if you can suggest methods to solve it.. i can surely verify once I am home..

midhun.madhu1987
 one year ago
Best ResponseYou've already chosen the best response.0and one thing... I tried many steps... lol

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Is that even math............ I'm afraid of my future........

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Also your very smart imqwerty considering I cant even read the problem right and your sitting here practically answering it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@midhunmadhu1987 We are in the same boat. I tried many ways, still not get the correct one. :)

midhun.madhu1987
 one year ago
Best ResponseYou've already chosen the best response.0@JoannaBlackwelder Could you have a look at it...

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.0Sure, I'll give it a shot.

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.0I get y2=[(a)(2x1)]/(x^2+1)^2 Is that what you get?

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.0are you sure there's not a typo in the question? https://gyazo.com/37935600cf0886aefbb297d1146e840c

JoannaBlackwelder
 one year ago
Best ResponseYou've already chosen the best response.0Yeah, ditto. I get really close, but not all of the terms cancel.

midhun.madhu1987
 one year ago
Best ResponseYou've already chosen the best response.0The same happened to me too @JoannaBlackwelder
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