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midhun.madhu1987

  • one year ago

Someone Please help me regarding this question...I tried to prove it, but was not successful...

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  1. midhun.madhu1987
    • one year ago
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  2. midhun.madhu1987
    • one year ago
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    Please note that: y1 = First Derivative y2 = Second Derivative

  3. anonymous
    • one year ago
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    What subject it is?

  4. imqwerty
    • one year ago
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    after differentiation y1 =e^arctan(x)/(x^2 +1) y2=[-e^arctan(x) (2x+1)]/(x^2 +1)^2

  5. imqwerty
    • one year ago
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    lets call e^arctan(x)=a so we have y1=a/(x^2 +1) y2=[(-a)(2x+1)]/(x^2+1)^2

  6. imqwerty
    • one year ago
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    it would be long if we put the values of y1,y2 ad y in the equation so lets think of a shorter method...

  7. midhun.madhu1987
    • one year ago
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    I am so sorrry... Since I am at the office now.. wont be able to look at it... if you can suggest methods to solve it.. i can surely verify once I am home..

  8. imqwerty
    • one year ago
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    ok :)

  9. midhun.madhu1987
    • one year ago
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    and one thing... I tried many steps... lol

  10. anonymous
    • one year ago
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    Is that even math............ I'm afraid of my future........

  11. imqwerty
    • one year ago
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    LOOOL XD

  12. anonymous
    • one year ago
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    Also your very smart imqwerty considering I cant even read the problem right and your sitting here practically answering it

  13. anonymous
    • one year ago
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    @midhun-madhu1987 We are in the same boat. I tried many ways, still not get the correct one. :)

  14. IrishBoy123
    • one year ago
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    @oldrin.bataku

  15. midhun.madhu1987
    • one year ago
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    @JoannaBlackwelder Could you have a look at it...

  16. JoannaBlackwelder
    • one year ago
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    Sure, I'll give it a shot.

  17. JoannaBlackwelder
    • one year ago
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    I get y2=[(-a)(2x-1)]/(x^2+1)^2 Is that what you get?

  18. IrishBoy123
    • one year ago
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    are you sure there's not a typo in the question? https://gyazo.com/37935600cf0886aefbb297d1146e840c

  19. JoannaBlackwelder
    • one year ago
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    Yeah, ditto. I get really close, but not all of the terms cancel.

  20. midhun.madhu1987
    • one year ago
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    The same happened to me too @JoannaBlackwelder

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is replying to Can someone tell me what button the professor is hitting...

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