Someone Please help me regarding this question...I tried to prove it, but was not successful...

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Someone Please help me regarding this question...I tried to prove it, but was not successful...

Mathematics
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Please note that: y1 = First Derivative y2 = Second Derivative
What subject it is?

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Other answers:

after differentiation y1 =e^arctan(x)/(x^2 +1) y2=[-e^arctan(x) (2x+1)]/(x^2 +1)^2
lets call e^arctan(x)=a so we have y1=a/(x^2 +1) y2=[(-a)(2x+1)]/(x^2+1)^2
it would be long if we put the values of y1,y2 ad y in the equation so lets think of a shorter method...
I am so sorrry... Since I am at the office now.. wont be able to look at it... if you can suggest methods to solve it.. i can surely verify once I am home..
ok :)
and one thing... I tried many steps... lol
Is that even math............ I'm afraid of my future........
LOOOL XD
Also your very smart imqwerty considering I cant even read the problem right and your sitting here practically answering it
@midhun-madhu1987 We are in the same boat. I tried many ways, still not get the correct one. :)
@oldrin.bataku
@JoannaBlackwelder Could you have a look at it...
Sure, I'll give it a shot.
I get y2=[(-a)(2x-1)]/(x^2+1)^2 Is that what you get?
are you sure there's not a typo in the question? https://gyazo.com/37935600cf0886aefbb297d1146e840c
Yeah, ditto. I get really close, but not all of the terms cancel.
The same happened to me too @JoannaBlackwelder

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