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f/g means divide f's expression by g's
divide f(x) by g(x) and take out the point in which g(x) is zero. so domain will be real numbers - of that point
@phi can i try this one? you can verify me if i am wrong
okay so like -20x^2 + 14x + 12 / 5x - 6 That's what I thought it was initially, but not sure.
it might be easier to multiply g(x) by the choice and see if you get f(x) or, you can try dividing g(x) into f(x) of course, you need to know how to divide polynomials by another polynomial
yes you are going the right way... just be careful with the domain.
@lily1021 do you know how to divide polynomials?
if you learn anything in math, it is *no divide by zero* if there is an "x" value that makes the bottom zero , we do not allow x to be that number
@phi you are right
yes @phi if g(x) is zero then it wont be defined
But, do you know why you can never divide by 0 @lily1021 ?
because you can't find an answer
i've divided polynomials before but i'm usually a hit or miss with them
Yes, that makes it "undefined."
Division by 0 has no meaning in the set of real numbers.
so I'm not going to divide then? Idk my heads spinning
Just like a word that has no meaning is undefined in the dictionary :-)
Yes, first you divide one polynomial into the other.
Second you set the divisor equal to 0 and find the values that make the divisor equal to 0 and exclude them in your answer.
Does that procedure make sense @lily1021 ?
yes I have that down on my paper
just like that too
i'm getting 5x-6
okay I see that
yeah I was wondering if +12 was supposed to be there too. Yep
What is the second thing we need to do now?
set the divisor?
to what? and why?
@skullpatrol good job in helping her
thanks @arindameducationusc :-)
I'm not sure why. You kinda just told me so I went with it if I'm being honest.
you said the divisor has to be = to 0
Let me show you why...