Help with algebra 2 please

- anonymous

Help with algebra 2 please

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- arindameducationusc

hello

- phi

f/g means divide f's expression by g's

- arindameducationusc

divide f(x) by g(x)
and take out the point in which g(x) is zero.
so domain will be real numbers - of that point

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## More answers

- arindameducationusc

@phi
can i try this one? you can verify me if i am wrong

- anonymous

@arindameducationusc hi

- anonymous

okay so like -20x^2 + 14x + 12 / 5x - 6 That's what I thought it was initially, but not sure.

- phi

it might be easier to multiply g(x) by the choice and see if you get f(x)
or, you can try dividing g(x) into f(x)
of course, you need to know how to divide polynomials by another polynomial

- arindameducationusc

yes you are going the right way...
just be careful with the domain.

- arindameducationusc

@lily1021 do you know how to divide polynomials?

- phi

if you learn anything in math, it is *no divide by zero*
if there is an "x" value that makes the bottom zero , we do not allow x to be that number

- arindameducationusc

@phi you are right

- arindameducationusc

yes @phi
if g(x) is zero then it wont be defined

- skullpatrol

But, do you know why you can never divide by 0 @lily1021 ?

- anonymous

because you can't find an answer

- anonymous

i've divided polynomials before but i'm usually a hit or miss with them

- skullpatrol

Yes, that makes it "undefined."

- anonymous

right

- skullpatrol

Division by 0 has no meaning in the set of real numbers.

- anonymous

so I'm not going to divide then? Idk my heads spinning

- skullpatrol

Just like a word that has no meaning is undefined in the dictionary :-)

- skullpatrol

Yes, first you divide one polynomial into the other.

- skullpatrol

Second you set the divisor equal to 0 and find the values that make the divisor equal to 0 and exclude them in your answer.

- skullpatrol

Does that procedure make sense @lily1021 ?

- skullpatrol

|dw:1440074722497:dw|

- anonymous

yes I have that down on my paper

- anonymous

just like that too

- anonymous

i'm getting 5x-6

- skullpatrol

|dw:1440074924187:dw|

- anonymous

okay I see that

- skullpatrol

|dw:1440075267669:dw|

- anonymous

yeah I was wondering if +12 was supposed to be there too. Yep

- skullpatrol

What is the second thing we need to do now?

- anonymous

set the divisor?

- skullpatrol

to what? and why?

- anonymous

to 0

- skullpatrol

yes, why?

- arindameducationusc

@skullpatrol
good job in helping her

- skullpatrol

thanks @arindameducationusc :-)

- anonymous

I'm not sure why. You kinda just told me so I went with it if I'm being honest.

- anonymous

you said the divisor has to be = to 0

- skullpatrol

Let me show you why...

- skullpatrol

|dw:1440075940828:dw|

- skullpatrol

|dw:1440076091981:dw|