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anonymous
 one year ago
PLEASE HELP, IM LOST ON THIS QUESTION Given the equation 2Square root of x minus 5 = 2, solve for x and identify if it is an extraneous solution.
anonymous
 one year ago
PLEASE HELP, IM LOST ON THIS QUESTION Given the equation 2Square root of x minus 5 = 2, solve for x and identify if it is an extraneous solution.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@@peachpi @imqwerty @arindameducationusc @godgirl122 @heretohelpalways please help I'm confused

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i did already but i got 2x5=4

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0or would it be 4x5=4?

imqwerty
 one year ago
Best ResponseYou've already chosen the best response.2is this the question  \[\sqrt[2]{x5}=2 \]??

imqwerty
 one year ago
Best ResponseYou've already chosen the best response.2ok so when u square both the sides \[(\sqrt[2]{x+5})^2 =2^2\] what will be the RHS after squaring? :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sorry , whats the RHS again?

imqwerty
 one year ago
Best ResponseYou've already chosen the best response.2RHS=right hand side :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok thanks it would be

imqwerty
 one year ago
Best ResponseYou've already chosen the best response.2right hand side of the equation

imqwerty
 one year ago
Best ResponseYou've already chosen the best response.2yes and what wuld be the Left hand side?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes, now we solve for the variable and get 1 right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0please help i don't know what to do after this step

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@imqwerty wait don't go please help

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0well my answer choices are these : x= 6, solution is not extraneous x = 6, solution is extraneous x = 11, solution is not extraneous x = 11, solution is extraneous

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and none of those are 1 so i don't know what to do next

imqwerty
 one year ago
Best ResponseYou've already chosen the best response.2we got x5 = 1 add 5 to both sides u get x=6

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok thank you so much

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how do i know if it is extraneous or not

imqwerty
 one year ago
Best ResponseYou've already chosen the best response.2and the solution is not extraneous cause when u put x=6 is a true solution :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok so if its a true solution its always not extraneous?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok, thank you for all of your help! it was much appreciated
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