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anonymous
 one year ago
PLEASE HELP NOT QUITE SURE ON THIS QUESTION Given the equation −4Square root of x minus 3 = 12, solve for x and identify if it is an extraneous solution.
anonymous
 one year ago
PLEASE HELP NOT QUITE SURE ON THIS QUESTION Given the equation −4Square root of x minus 3 = 12, solve for x and identify if it is an extraneous solution.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0this is the equation: \[\sqrt[4]{x3} = 12\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1\[\huge\rm 4\sqrt{x3}=12\] first move the 4 to the right side

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1it's not 4th root right ? is it 4 (sqrt{x3} ??

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes you have it right

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1okay then first move the 4 to the right side how would do that ? divide , multiply add , or subtract ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1now it's 4 times sqrt{x3} what is opposite of multiplication ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1yes right so divide both side by 4

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1\[\sqrt{x3}=3\] now take square both sides to cancel out the square root

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1\[\huge\rm (\sqrt{x3})^2=(3)^2\] when you take even power of NEGATIVE you will ALAWAYS get positive answer

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1sp (3)^2 =? it's same as 3 times 3

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and then you would add 3 to get positive 12

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and then would it be extraneous or not extraneous?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1okay to check if it's extraneous or not substitute x for 12 in the original equation

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1if both sides are equal then 12 isn't extraneous

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0both sides came out equal so its not extraneous

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1how did you get equal sides ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0honestly i don't know

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1\[4\sqrt{123}=12\] now solve

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1show me how did you do it ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0im not sure how i did it but could you show me how to do it the right way please?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i just guessed because i wasn't sure how to do it, the 4 on the outside of the sqr root confuses me

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1okay so we replaced x with 12 right now solve \[4\sqrt{123}=12\] 123 and then take square root

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1seee i knew it remember it's not 4 it's 4

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1hint: \[1\cancel{=}1\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i got \[\sqrt[16]{9} =12\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0that 16 isnt an exponent

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1hmm how did you get 16? 123 = ??

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1don't take square \[4\sqrt{123}\] you should substitute x for 12 into the original equation

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1123= 9 right \[4\sqrt{9}\] now solve

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sorry as you can tell i struggle with algebra

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no so they are extraneous

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the solution is not extraneous

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0solution is extraneous right ? @Nnesha

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1which one is it extraneous or not ? like i said if you get equal sides THEN 12 is not extraneous

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.112=12 both sides are equal ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no they are not equal so it is extraneous

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thanks so much for all your help that took awhile but thank you
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