PLEASE HELP NOT QUITE SURE ON THIS QUESTION Given the equation −4Square root of x minus 3 = 12, solve for x and identify if it is an extraneous solution.

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this is the equation: \[\sqrt[-4]{x-3} = 12\]

\[\huge\rm -4\sqrt{x-3}=12\]
first move the -4 to the right side

it's not 4th root right ?
is it -4 (sqrt{x-3} ??

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