ALGEBRA!! Factor completely over the complex numbers. x^4+18x^2+81 Any idea how the final answer looked like? (x^2+9)(x^2+9)

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ALGEBRA!! Factor completely over the complex numbers. x^4+18x^2+81 Any idea how the final answer looked like? (x^2+9)(x^2+9)

Mathematics
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yea that's correct

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Other answers:

oh you need it over complex numbers
Yep maybe (x^2+9i)^2 (x^2+9i)^2 ?
fill in the blanks x^2 + 9 = (x 3i)(x 3i) ?
(x^2+3i)(x^2+3i) ?
what signs go in the parentheses?
Both positives
no and its x not x^2
x^2 + 9 = (x + 3i)(x - 3i)
Oh i get it
x^4+18x^2+81 this is the that will be factored over the complex numbers
so complete factors are (x + 3i)(x - 3i)(x + 3i)(x - 3i))
Is that the same with (x+3i)^2(x-3i)^2 ??
yes you can write it that way
are you happy about multiplying these imaginary numbers? -3i * + 3i = -9 * i^2 = -9 * - 1 = +9 because i^2 = -1
|dw:1440088856517:dw|
Looks like this?
1 Attachment
- where did you get that from? its not x^2 it is x
If you expanded that the first term would be x^8 not x^4
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thats it
Thanks! :)
yw
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