anonymous
  • anonymous
Below are the data collected from two random samples of 100 members of a large travel club regarding the type of vacation they prefer: Sample Adventure Beach Cruise Ski A 73 4 18 3 B 71 6 22 1
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
anonymous
  • anonymous
Which of the following inferences can be made based on the data? Most members prefer a beach vacation. Most members prefer a cruise vacation. More members prefer a cruise vacation and a ski vacation than a beach vacation. More members prefer a beach vacation and a cruise vacation than an adventure vacation.
anonymous
  • anonymous
@Michele_Laino i think its C. not sure

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Michele_Laino
  • Michele_Laino
you have to compute the singles frequencies, namely the frequencies for a beach vacation are: 4/100 =0.04 for group A 6/100=0.06 for group B by the way group A contains 98 elements
anonymous
  • anonymous
OK
Michele_Laino
  • Michele_Laino
fro cruise vacation we have: 18/100=0.18 for group A 22/100=0.22 for group B
Michele_Laino
  • Michele_Laino
for cruise vacation and ski vacation we have: (18+3)/100=21/100=0.21 group A (22+1)/100= 23/100=0.23 group B
anonymous
  • anonymous
oh OK so would my answer then be D. @Michele_Laino
anonymous
  • anonymous
well actually no cause an Adventure vacation is preferred alot :(
Michele_Laino
  • Michele_Laino
for beach and cruise vacation we have: (18+4)/100= 0.22 group A (22+6)/100= 0.28 group B and adventure vacation: 73/100=0.73 group A 71/100=0.71 group B
Michele_Laino
  • Michele_Laino
answer D is not correct, since 0.73>0.22 and 0.71>0.28, am I right?
Michele_Laino
  • Michele_Laino
whereas: 0.21 > 0.04, and 0.23> 0.06 so, what can you conclude?
anonymous
  • anonymous
was i right then about C. @Michele_Laino
Michele_Laino
  • Michele_Laino
yes! since for beach vacation and cruise vacation the frequencies are less than 0.5
anonymous
  • anonymous
Thankk You!!! could u please help me with a few more? @Michele_Laino
Michele_Laino
  • Michele_Laino
ok!

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