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is it 4!

In my method the answer will be this.(Giving the same as nnesha's result):
\(\huge ^7C_4\times 4!\)

\[\huge \ldots=P_{(7,4)} \]

the problem is equivalent to that of
finding number of 4 letters words using 7 different letters

i think it as only 4 persons can be seated and the 4 persons can be arranged in 4! ways

Simplicity @ganeshie8 :D lol

4! is true if you just have 4 chairs

....and only 4 people..

yes i just have 4 chairs

** 4! is true if you just have 4 chairs and 4 people

You can take a simple example like 4 people and 3chairs and get the feeling @mathmath333

is there any website that shows permutations and combinations list

python has got the function permutations in itertools module.

ABC
ACB
ABD
ADB
ACD
ADC
BCD
BDC

you may use this for combinations
https://jsfiddle.net/ganeshie8/r2hjr3js/4/

nice

right you should get 7C4 = 35 combinations

yep... If you aren't allowed to use the same number twice.

ok thnx

from the past 2 weeks i m getting this very annoying bug
I have to reload the page every time to type and my question gets changed to this page

you're not alone, everybody is facing that issue
@Astrophysics is there any fix yet ?

me too...

lol how can so many people tolerate this

previuosly it happened only once in an hour but recently it get to on every long text i type