How many moles of ethylene (C2H4) can react with 12.9 liters of oxygen gas at 1.2 atmospheres and 297 Kelvin?
C2H4(g) + 3O2(g) yields 2CO2(g) + 2H2O(g)
I have a test later today, please show me how to do this so I'll know what to do on the test. Thank you. :)

- anonymous

- jamiebookeater

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- sjg13e

I'm pretty sure this is a PVNRT problem. Do you know the ideal gas law formula?

- anonymous

Yes

- sjg13e

Okay, well the first thing you need to go is find out how many moles of Oxygen you have, using the ideal gas law formula

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- sjg13e

Can you show me how to do that?

- anonymous

I think so, one sec let me look

- anonymous

I attempted it by plugging it into the formula before but I just don't think I got the right answer

- sjg13e

You should know the formula if you have a test later :s but it's really easy to remember! It's PVNRT. Or PV = nRT
where
p = pressure (atm)
v = volume (L)
R = gas constant
n = moles (mol)
t = temperature (T)

- sjg13e

So, use the values given in the problem to solve for n, which equals the number of moles of Oxygen gas. What value did you get?

- anonymous

I got 0.634 moles

- sjg13e

Okay awesome. So there's 0.634 moles of Oxygen. Since you have a chemical equation and the moles of Oxygen, do you think you sort of know how to get to the moles of C2H4?

- anonymous

That's where I get lost lol

- sjg13e

That's okay. That's where most people get lost. So, at this point we have to use dimensional analysis. Just a fancy word of saying to get from one thing to another. My high school chem teacher used to call it train-and-caboose

- sjg13e

|dw:1440095137685:dw|

- sjg13e

You have to use the chemical equation to determine the ratio. So, for every 3 mol of Oxygen there's 1 mol of C2H4

- sjg13e

|dw:1440095235516:dw|
make sure to cross out your units

- anonymous

Ok thank you, I'll try it :)

- sjg13e

Okay! Practice makes perfect! Let me know if you have anymore questions

- anonymous

Thanks!

- anonymous

Ok, sorry I'm really tired haha. How am I supposed to plug it in?

- anonymous

- sjg13e

What do you mean? Can you clarify? Plug in what? Do you mean the ideal gas law formula or dimensional analysis?

- anonymous

dimensional analysis

- sjg13e

Oh okay, well that's a little different. The only way to really understand it is by doing practice problems, but I generally use this sort of thinking:
|dw:1440096529907:dw|

- sjg13e

heres a link that might help http://www.katmarsoftware.com/articles/railroad-track-unit-conversion.htm

- anonymous

Ohh I see, thank you so much

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