anonymous
  • anonymous
A right triangle has base (x - 5) units and height (4x - 10) units. Part A: What is the square of the length of the hypotenuse of the triangle?
Mathematics
katieb
  • katieb
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Vocaloid
  • Vocaloid
"square of the length of the hypotenunse" = (base)^2 + (height)^2
anonymous
  • anonymous
(x-5)^2 + (4x -10)^2
anonymous
  • anonymous

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Vocaloid
  • Vocaloid
correct
anonymous
  • anonymous
Solve what you've written out.
Vocaloid
  • Vocaloid
oh, well, I guess you could try expanding it (x-5)^2 = (x-5)(x-5) = ? (4x-10)^2 = (4x-10)(4x-10) = ?
anonymous
  • anonymous
x^2-10x+25 x^2 -20x+100
Vocaloid
  • Vocaloid
first one looks good check the second one again
anonymous
  • anonymous
oh 4x sorry
Vocaloid
  • Vocaloid
nope, not quite... (4x)*(4x) = ?
anonymous
  • anonymous
no i did x instead of 4x
Vocaloid
  • Vocaloid
let's start again (4x-10)^2 = (4x-10)(4x-10) = ?
Vocaloid
  • Vocaloid
remember foil? first we multiply the first terms in each parentheses (4x)*(4x) = ?
anonymous
  • anonymous
16x^2-80x+100
Vocaloid
  • Vocaloid
yup! that looks much better now we have: x^2-10x+25 16x^2-80x+100
anonymous
  • anonymous
Okay
Vocaloid
  • Vocaloid
now we add everything together combine like terms: x^2 + 16x^2 = ?
anonymous
  • anonymous
16x^2-90x+125 i forgot if you add the exponents or not
anonymous
  • anonymous
17x^2-90x+125 sorry
anonymous
  • anonymous
@Vocaloid is that it?
Vocaloid
  • Vocaloid
yup! good job
anonymous
  • anonymous
That doesnt seem like the right answer to the question but okay

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