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anonymous

  • one year ago

A right triangle has base (x - 5) units and height (4x - 10) units. Part A: What is the square of the length of the hypotenuse of the triangle?

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  1. Vocaloid
    • one year ago
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    "square of the length of the hypotenunse" = (base)^2 + (height)^2

  2. anonymous
    • one year ago
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    (x-5)^2 + (4x -10)^2

  3. anonymous
    • one year ago
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    @Vocaloid

  4. Vocaloid
    • one year ago
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    correct

  5. anonymous
    • one year ago
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    Solve what you've written out.

  6. Vocaloid
    • one year ago
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    oh, well, I guess you could try expanding it (x-5)^2 = (x-5)(x-5) = ? (4x-10)^2 = (4x-10)(4x-10) = ?

  7. anonymous
    • one year ago
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    x^2-10x+25 x^2 -20x+100

  8. Vocaloid
    • one year ago
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    first one looks good check the second one again

  9. anonymous
    • one year ago
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    oh 4x sorry

  10. Vocaloid
    • one year ago
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    nope, not quite... (4x)*(4x) = ?

  11. anonymous
    • one year ago
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    no i did x instead of 4x

  12. Vocaloid
    • one year ago
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    let's start again (4x-10)^2 = (4x-10)(4x-10) = ?

  13. Vocaloid
    • one year ago
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    remember foil? first we multiply the first terms in each parentheses (4x)*(4x) = ?

  14. anonymous
    • one year ago
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    16x^2-80x+100

  15. Vocaloid
    • one year ago
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    yup! that looks much better now we have: x^2-10x+25 16x^2-80x+100

  16. anonymous
    • one year ago
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    Okay

  17. Vocaloid
    • one year ago
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    now we add everything together combine like terms: x^2 + 16x^2 = ?

  18. anonymous
    • one year ago
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    16x^2-90x+125 i forgot if you add the exponents or not

  19. anonymous
    • one year ago
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    17x^2-90x+125 sorry

  20. anonymous
    • one year ago
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    @Vocaloid is that it?

  21. Vocaloid
    • one year ago
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    yup! good job

  22. anonymous
    • one year ago
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    That doesnt seem like the right answer to the question but okay

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