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anonymous

  • one year ago

Sums of consecutive integers

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  1. anonymous
    • one year ago
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    The sum of 3 consecutive odd numbers is 117.What is the first number in this sequence?

  2. kaitlyn_nicole
    • one year ago
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    31

  3. mathmate
    • one year ago
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    @kaitlyn_nicole \(31+33+35=99\ne 117\) Perhaps a typo?

  4. zzr0ck3r
    • one year ago
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    if I have 3 consecutive odd numbers, then they will be of the form n, n+2, n+4 we want to add them and get 117, so n+(n+2)+(n+4)=117

  5. anonymous
    • one year ago
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    no no typo

  6. zzr0ck3r
    • one year ago
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    he was not saying you have a typo @jamesr

  7. anonymous
    • one year ago
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    o

  8. anonymous
    • one year ago
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    but i dont understand this

  9. kaitlyn_nicole
    • one year ago
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    its 37 sorry

  10. anonymous
    • one year ago
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    ugh nvm

  11. kaitlyn_nicole
    • one year ago
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    \[37+39+41=117\]

  12. mathmate
    • one year ago
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    @kaitlyn_nicole Excellent, now can you explain to @jamesr how you got it so that he can solve similar problems?

  13. kaitlyn_nicole
    • one year ago
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    you do n+(n+2)+(n+4) = 117 thats the equation, tbh i have a very weird way of doing things but i mainly predicted what n was and worked my way from there.

  14. mathmate
    • one year ago
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    @kaitlyn_nicole I know your way, "guess and check", that's the fastest possible way, but does not work in all cases. We still have to know the proper way to do things to fall back on. Good job!

  15. zzr0ck3r
    • one year ago
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    I think it's best to help with the set up, with lots of explanation, and let them finish.

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