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sjg13e
 one year ago
Help with a calculus problem (integration by parts)
sjg13e
 one year ago
Help with a calculus problem (integration by parts)

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sjg13e
 one year ago
Best ResponseYou've already chosen the best response.1\[integrate \ln(2x+1)dx\]

sjg13e
 one year ago
Best ResponseYou've already chosen the best response.1I have some work, give me a few minutes to input it

sjg13e
 one year ago
Best ResponseYou've already chosen the best response.1\[\int\limits_{}^{}\ln(2x+1)dx = x*\ln(2x+1)  \int\limits_{}^{}\frac{ 2x }{ 2x +1 }\]

sjg13e
 one year ago
Best ResponseYou've already chosen the best response.1I don't know how to take the integral of 2x / 2x + 1. I've viewed solutions online and I've seen...

sjg13e
 one year ago
Best ResponseYou've already chosen the best response.1I don't know why they split it into (2x  1 + 1)/2x +1 Everything else I can do, except I just don't understand that part

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1do you still remember how to do "long division" ?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1dw:1440095909160:dw

sjg13e
 one year ago
Best ResponseYou've already chosen the best response.1lol, i'm not gonna lie, it's been a while. but i can do it! thanks for answering. The way I initially approached it was by doing \[2\int\limits_{}^{}x * \frac{ 1 }{ 2x +1 }\] and then using \[uv  \int\limits_{}^{}vdu\] to solve. so maybe that's why i didn't initially think of doing long division

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1that gives you back the original integrand haha!

sjg13e
 one year ago
Best ResponseYou've already chosen the best response.1yeah that's why i was like what am i doing wrong?? haha

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1ikr! review this quick for long division https://www.khanacademy.org/math/algebra2/polynomial_and_rational/dividing_polynomials/v/polynomialdivision

sjg13e
 one year ago
Best ResponseYou've already chosen the best response.1thanks so much for your help! i'll check the link out
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