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steve816

  • one year ago

This is an algebra 2 question that requires some skill, but help would be greatly appreciated!

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  1. steve816
    • one year ago
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    \[\frac{ x }{ (x-1)^{2} }+\frac{ 2 }{ x }-\frac{ x+1 }{ x ^{3}-x ^{2} }\]

  2. steve816
    • one year ago
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    Simplify please!

  3. anonymous
    • one year ago
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    Looking for someone to walk you through it?

  4. steve816
    • one year ago
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    Well, actually jsut the answer to the simplified equation would be good enough!

  5. anonymous
    • one year ago
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    that's why I asked. We're not allowed to give answers here as it doesn't really benefit anyone. http://openstudy.com/code-of-conduct If you just want the answer try an online calculator like wolframalpha.com

  6. steve816
    • one year ago
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    Well then please go ahead and walk me through, that would be still great.

  7. bmmoffattb
    • one year ago
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    I'll help you.

  8. bmmoffattb
    • one year ago
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    (x/x^2-1) + (2/x) + (x+1/x^3-x^2) =(x^-1/-1) + (2/x) + (x^-4 +1)

  9. bmmoffattb
    • one year ago
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    =(x^-1/-1) + (2x^-1) + (x^-4 +1)

  10. bmmoffattb
    • one year ago
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    =(x^-1/-1) + 2x^-5 +1

  11. bmmoffattb
    • one year ago
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    Not sure what to do from there. It's been a couple years since I've done Algebra 2.

  12. bmmoffattb
    • one year ago
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    I'm sure there are laws that tell you what to do.

  13. anonymous
    • one year ago
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    Factor the third denominator to get \[x^2(x-1)\]

  14. anonymous
    • one year ago
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    So now the 3 denominators are (x- 1)², x, and x²(x -1) the least common denominator needs to have the maximum of each factor. So we need both x and (x -1) twice LCD = \(x^2(x-1)^2\)

  15. anonymous
    • one year ago
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    To make all 3 fraction match the LCD you have to multiply them by different factors. Multiply the first by \[\frac{ x^2 }{ x^2 }\] Multiply the 2nd by \[\frac{ x(x-1)^2 }{ x(x-1)^2 }\] Multiply the 3rd by \[\frac{ x-1 }{ x-1 }\]

  16. anonymous
    • one year ago
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    the problem is now\[\frac{ x(x^2) }{ x^2(x-1)^{2} }+\frac{ 2x(x-1) }{ x(x)(x-1) }-\frac{ (x+1)(x-1) }{ x^2(x-1)^2 }\]

  17. anonymous
    • one year ago
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    \[\frac{ x^2+2x(x-1)-(x+1)(x-1) }{ x^2(x-1)^2 }\] Simplify the numerator and see if anything cancels with the denominator after

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