steve816
  • steve816
This is an algebra 2 question that requires some skill, but help would be greatly appreciated!
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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steve816
  • steve816
\[\frac{ x }{ (x-1)^{2} }+\frac{ 2 }{ x }-\frac{ x+1 }{ x ^{3}-x ^{2} }\]
steve816
  • steve816
Simplify please!
anonymous
  • anonymous
Looking for someone to walk you through it?

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steve816
  • steve816
Well, actually jsut the answer to the simplified equation would be good enough!
anonymous
  • anonymous
that's why I asked. We're not allowed to give answers here as it doesn't really benefit anyone. http://openstudy.com/code-of-conduct If you just want the answer try an online calculator like wolframalpha.com
steve816
  • steve816
Well then please go ahead and walk me through, that would be still great.
bmmoffattb
  • bmmoffattb
I'll help you.
bmmoffattb
  • bmmoffattb
(x/x^2-1) + (2/x) + (x+1/x^3-x^2) =(x^-1/-1) + (2/x) + (x^-4 +1)
bmmoffattb
  • bmmoffattb
=(x^-1/-1) + (2x^-1) + (x^-4 +1)
bmmoffattb
  • bmmoffattb
=(x^-1/-1) + 2x^-5 +1
bmmoffattb
  • bmmoffattb
Not sure what to do from there. It's been a couple years since I've done Algebra 2.
bmmoffattb
  • bmmoffattb
I'm sure there are laws that tell you what to do.
anonymous
  • anonymous
Factor the third denominator to get \[x^2(x-1)\]
anonymous
  • anonymous
So now the 3 denominators are (x- 1)², x, and x²(x -1) the least common denominator needs to have the maximum of each factor. So we need both x and (x -1) twice LCD = \(x^2(x-1)^2\)
anonymous
  • anonymous
To make all 3 fraction match the LCD you have to multiply them by different factors. Multiply the first by \[\frac{ x^2 }{ x^2 }\] Multiply the 2nd by \[\frac{ x(x-1)^2 }{ x(x-1)^2 }\] Multiply the 3rd by \[\frac{ x-1 }{ x-1 }\]
anonymous
  • anonymous
the problem is now\[\frac{ x(x^2) }{ x^2(x-1)^{2} }+\frac{ 2x(x-1) }{ x(x)(x-1) }-\frac{ (x+1)(x-1) }{ x^2(x-1)^2 }\]
anonymous
  • anonymous
\[\frac{ x^2+2x(x-1)-(x+1)(x-1) }{ x^2(x-1)^2 }\] Simplify the numerator and see if anything cancels with the denominator after

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