anonymous
  • anonymous
Help!
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
Now, this position function is a function of time. We can see that, plugging in 0 seconds for t will give us a result of 144 feet. Knowing this we can deduce that the paper clip will hit the ground when the left side of the function is 0. After this, we can solve for how much time it will take for the paper clip to hit the ground by solving for t. Then we can use the gravity constant, time it takes to hit the ground and initial velocity to figure out the final velocity.
phi
  • phi
I would find at what time the paper clip hits the ground s(t)=0 when on the ground in other words, find t when \[ -16t^2 +144= 0\]
anonymous
  • anonymous
-16t^2=-144 t^2=9 t=3

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phi
  • phi
next, velocity is the derivative of s(t) (this is calculus , right?) v(t)= -32 t plug in t=3 to find the velocity at time t=3 (which is when it hits the ground)
anonymous
  • anonymous
Yes it is and I got v(t)=-96
phi
  • phi
yes -96 ft/sec (negative means it is moving down)
anonymous
  • anonymous
Okay thank you so much!

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