If 45g of LiF dissolved in 1.8kg of water, what would be the expected change in boiling point? The boiling point constant for water (Kb) is 0.51 degrees C/m. - 0.49 degrees C - 0.98 degrees C - 1.9 degrees C - 3.5 degrees C Im not sure which one it is I got both 0.49 and 0.98 Please Help. I will medal.

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If 45g of LiF dissolved in 1.8kg of water, what would be the expected change in boiling point? The boiling point constant for water (Kb) is 0.51 degrees C/m. - 0.49 degrees C - 0.98 degrees C - 1.9 degrees C - 3.5 degrees C Im not sure which one it is I got both 0.49 and 0.98 Please Help. I will medal.

Chemistry
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What calculations did you perform?
I ended up going with the first answer 0.49 based on my calculations
did you have \(\large \Delta T=i*K_b*m=2*(0.51~^oC/m)*\dfrac{(\frac{45~g}{25.9~g/mol})}{1.8~kg}\)

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No and when I solve yours I get 25 which isn't a choice
you're solving it incorrectly, because i get 0.984555984555984583356
I'm so lost
I don't know who's right
I'm right lol you got 0.49 because you didn't take into account that i=2
Okay thank you so much
CaN I ask another
no problem, and sure, shoot.
A 65 gram of some unknown metal at 100.0 deg C is added to 100.8grams at 22 degrees Celsius. The temperature of the water rises 27.0 degrees C. Of the specific heat capacity of liquid water is 4.18 J/degC*g, what is the specific heat of the metal?
The choices are -2.25 J/(C*g) -1.75 J/(C*g) -0.444 J/(C*g) -0.324 J/(C*g)
I don't know Where to start @arronq and how to get the answer
So this is a little complicated but bare with me. First you use the mass of the water, the specific heat capacity and the change of temperature the water had to find the heat lost by the metal. Now that you have the heat lost by the metal, you can use the mass of the metal and the temperature change of the metal (along with the heat you found in the first part) to solve for the specific heat capacity. The equation is \(\sf q=m*C_p*\Delta T\) q= heat m=mass Cp=specific heat capacity \(\Delta T\)=change in Temp
Based on what your saying and what I do know I'm getting 0.444 with my calculations. Is that correct?
show your calculations
I can't I don't have a camera and my computers to old to type them in
so how am i supposed to see if you're doing it right?
I think I am I just need to double check the final response with you and if I get it wrong I'll try it a different way until I'm doing it right
its right
Okay thank you so much
no problem

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