If 45g of LiF dissolved in 1.8kg of water, what would be the expected change in boiling point? The boiling point constant for water (Kb) is 0.51 degrees C/m.
- 0.49 degrees C
- 0.98 degrees C
- 1.9 degrees C
- 3.5 degrees C
Im not sure which one it is I got both 0.49 and 0.98 Please Help. I will medal.

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What calculations did you perform?

I ended up going with the first answer 0.49 based on my calculations

did you have \(\large \Delta T=i*K_b*m=2*(0.51~^oC/m)*\dfrac{(\frac{45~g}{25.9~g/mol})}{1.8~kg}\)

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