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anonymous

  • one year ago

What is the missing exponent? (6 )-4 = 620

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  1. anonymous
    • one year ago
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    (6 )^-4 = 620 (the negative 4 is an exponent)

  2. campbell_st
    • one year ago
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    so are you looking for the exponent of 6...? as in \[(6^x)^{-4} = 620\]

  3. anonymous
    • one year ago
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    yes

  4. anonymous
    • one year ago
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    @campbell_st

  5. campbell_st
    • one year ago
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    ok... so using the power of a power law which means multiply the powers \[6^{-4x} = 620\] now you need logs to solve it take the log of both sides \[\ln(6^{-4x}) = \ln(620)\] applying the log laws for powers \[-4x \times \ln(6) = \ln(620)\] so \[-4x = \frac{\ln(620)}{\ln(6)}\] now solve for x

  6. anonymous
    • one year ago
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    I'm still confused, how do I solve for x?

  7. anonymous
    • one year ago
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    @campbell_st

  8. campbell_st
    • one year ago
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    so when you get a value for the log division, just divide it by -4

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