anonymous
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help!
Mathematics
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anonymous
  • anonymous
help!
Mathematics
chestercat
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
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anonymous
  • anonymous
A circular picture is 8 inches in diameter. Part A What is the area of the picture in square inches? A. 4π square inches B. 8π square inches C. 16π square inches D. 32π square inches Part B A frame that is 2 inches wide surrounds the picture. What is the total area of the picture and the frame in square inches? A. 4π square inches B. 12π square inches C. 36π square inches D. 40π square inches
anonymous
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anonymous
  • anonymous
\[A=\frac{ \pi d^2 }{ 4 }\] For the first one, substituted 8 for d and reduce
anonymous
  • anonymous
for the second, a 2" frame increases the diameter by 4 b/c of 2" on each side. Substitute 12 for d
anonymous
  • anonymous
anonymous
  • anonymous
i got 36 pi for B but i dont know A
anonymous
  • anonymous
they're exactly the same problem. Do 8^2 Then divide by 4
anonymous
  • anonymous
@Vocaloid am i right?
anonymous
  • anonymous
i got A for A
anonymous
  • anonymous
It looks like you did 8*2 8^2 = 8*8
anonymous
  • anonymous
im not ignoring her :) im listening and learning :)
anonymous
  • anonymous
oh yea i did 8*2 sorry, let me re-do it
anonymous
  • anonymous
i got 16 pi
anonymous
  • anonymous
yes 16π and 36π
anonymous
  • anonymous
ok thanks! i have a bunch more questions! can i tag you :)

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