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anonymous
 one year ago
Given the equation −4Square root of x minus 3 = 12, solve for x and identify if it is an extraneous solution.
x = 0, solution is not extraneous
x = 0, solution is extraneous
x = 12, solution is not extraneous
x = 12, solution is extraneous
anonymous
 one year ago
Given the equation −4Square root of x minus 3 = 12, solve for x and identify if it is an extraneous solution. x = 0, solution is not extraneous x = 0, solution is extraneous x = 12, solution is not extraneous x = 12, solution is extraneous

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imqwerty
 one year ago
Best ResponseYou've already chosen the best response.1ok so we have \[4\sqrt{x3}=12\]divide both sides by 4 we get\[\sqrt{x3}=3\]square both sides u get \[x3=9\]add 3 to both sides u get \[x=12\] Plug in x=12 in the original equation i.e, \[4\sqrt{x3}=12\]we get \[4\sqrt{123}=12\]simplifying we get\[4(3)=12\]\[12=12\]which doesn't makes any sense so x=12 is an extraneous solution :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ahhhh, i see. Thanks soooo much!

imqwerty
 one year ago
Best ResponseYou've already chosen the best response.1no problem :) u r welcome
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