## anonymous one year ago Given the equation −4Square root of x minus 3 = 12, solve for x and identify if it is an extraneous solution. x = 0, solution is not extraneous x = 0, solution is extraneous x = 12, solution is not extraneous x = 12, solution is extraneous

1. anonymous

Yes!

2. imqwerty

ok so we have -$-4\sqrt{x-3}=12$divide both sides by -4 we get$\sqrt{x-3}=-3$square both sides u get -$x-3=9$add 3 to both sides u get $x=12$ Plug in x=12 in the original equation i.e, $-4\sqrt{x-3}=12$we get $-4\sqrt{12-3}=12$simplifying we get-$-4(3)=12$$-12=12$which doesn't makes any sense so x=12 is an extraneous solution :)

3. anonymous

Ahhhh, i see. Thanks soooo much!

4. imqwerty

no problem :) u r welcome