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anonymous

  • one year ago

A quadratic equation is shown below: 3x2 - 16x + 2 = 0 Part A: Describe the solution(s) to the equation by just determining the radicand. Show your work. (3 points) Part B: Solve 9x2 + 3x - 2 = 0 by using an appropriate method. Show the steps of your work, and explain why you chose the method used. (4 points) Part C: Solve 3x2 - 10x + 2 = 0 by using a method different from the one you used in Part B. Show the steps of your work. (3 points)

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  1. anonymous
    • one year ago
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    start by writing down the quadratic equation, then identify the value for each variable.

  2. anonymous
    • one year ago
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    Ok, s the quadratic equation is 3x^2 - 16x + 2 = 0

  3. anonymous
    • one year ago
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    that's the equation for your parabola. The quadratic equation is used to find when and where a parabola crosses the x-axis. In other words, it identifies your x-intercepts.

  4. anonymous
    • one year ago
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    |dw:1440103710100:dw|

  5. anonymous
    • one year ago
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    that's the quadratic equation...parabolas are written as \[ax ^{2}+bx+c=0\]

  6. anonymous
    • one year ago
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    A = 3 B = -16 C = -2

  7. anonymous
    • one year ago
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    So then B2 - 4AC = 256 - (-24) = 280

  8. anonymous
    • one year ago
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    if you're on the first one, c isn't -2

  9. anonymous
    • one year ago
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    6 ± √ 280 x = —————— 6

  10. anonymous
    • one year ago
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    ohhhh

  11. anonymous
    • one year ago
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    Then this? A = 3 B = -16 C = 2 B2 - 4AC = 256 - 24 = 232

  12. anonymous
    • one year ago
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    16 ± √ 232 x = —————— 6

  13. anonymous
    • one year ago
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    right?

  14. anonymous
    • one year ago
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    yes...it's not going to be a rational number. sometimes teachers will ask that you simplify what's in the radical, but I wouldn't unless you know you have to.

  15. anonymous
    • one year ago
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    So what do I do then?

  16. anonymous
    • one year ago
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    Help anyone :(

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