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moazzam07
 one year ago
Trina's Toy Company charges $0.85 per pound to ship toys.
Part A: Write an equation to determine the total cost, c, to ship p pounds of toys. Use your equation to determine the cost of shipping 2 pounds of toys. (6 points)
Part B: If the company reduces the cost to ship toys by 0.05 per pound, write an equation to determine the total cost, c, to ship p pounds of toys with the reduced cost. (4 points)
moazzam07
 one year ago
Trina's Toy Company charges $0.85 per pound to ship toys. Part A: Write an equation to determine the total cost, c, to ship p pounds of toys. Use your equation to determine the cost of shipping 2 pounds of toys. (6 points) Part B: If the company reduces the cost to ship toys by 0.05 per pound, write an equation to determine the total cost, c, to ship p pounds of toys with the reduced cost. (4 points)

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jjwalton04
 one year ago
Best ResponseYou've already chosen the best response.1Which Part do you not understand?

moazzam07
 one year ago
Best ResponseYou've already chosen the best response.0Can you explain how to do both parts please @ jjwalton04

jjwalton04
 one year ago
Best ResponseYou've already chosen the best response.1Part a=\[0.85p=c\] is the main equation and we need to find the price for two pounds sowe plug in 2 for p and just solve 0.85*2=?

jjwalton04
 one year ago
Best ResponseYou've already chosen the best response.1So when your finished you should get 0.85*2=1.7 Theres A. Now for b, Step one 0.850.05 Step two 0.80*2=1.6

moazzam07
 one year ago
Best ResponseYou've already chosen the best response.0step one  0.8 step two 

jjwalton04
 one year ago
Best ResponseYou've already chosen the best response.1Lets see, we explained the price for two pounds and we explained the price for two pounds with the deducted price so...... Yeah

jjwalton04
 one year ago
Best ResponseYou've already chosen the best response.1Btw the format is p*x=c

jjwalton04
 one year ago
Best ResponseYou've already chosen the best response.1well price*pounds=cost

jjwalton04
 one year ago
Best ResponseYou've already chosen the best response.1Anytime, if you need me again just tag me
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